CODEWITHSUNDEEP
pythonpython-2.7calendardays
James Adams
James Adams

Reputation: 748

Printing the number of days in a given month and year [Python]

I've been trying to work out a way to accomplish what's in the title, without using any imported calendar/datetime libs from Python. There's little function at the top for checking whether or not the year is a leap year, which I want to be able to reference when printing the number of days in a given February, however I'm not too sure how to do so. (I've guessed with something like output. bla bla)

So far I've come up with something like this, which should make clear what I want to do, but I'm still a bit new to Python, so I would love a few tips/help on fixing up my code for the task.

# A function to determine if a year is a leap year.
# Do not change this function.
def is_leap_year (year):
    return (year % 4 == 0) and (year % 100 != 0) or (year % 400 == 0)

# You should complete the definition of this function:

 def days_in_month(month, year):

    if month == 'September' or month == 'April' or month == 'June' or month == 'November'
    print 30

    elseif month == 'January' or month == 'March' or month == 'May' or month== 'July' or month == 'August' or month == 'October'\
    or month== 'December'
     print 31

    elseif month == 'February' and output.is_leap_year = True
    print 29

    elseif month == 'February' and output.is_leap_year = False
    print 28

    else print 'Blank'

Ok I've fixed up my code, and it seems to output the correct data for every month but February:

# A function to determine if a year is a leap year.
# Do not change this function.
def is_leap_year (year):
    return (year % 4 == 0) and (year % 100 != 0) or (year % 400 == 0)

# You should complete the definition of this function:

def days_in_month(month, year):

    if month in ['September', 'April', 'June', 'November']:
        print 30

    elif month in ['January', 'March', 'May', 'July', 'August','October','December']:
        print 31        

    elif month == 'February' and is_leap_year == True:
        print 29

    elif month == 'February' and is_leap_year == False:
        print 28

Any hints to fix up outputting for February?

EDIT: Just needed to add the argument year when referencing the first function. Here is the 100% working code for future reference:

# A function to determine if a year is a leap year.
# Do not change this function.
def is_leap_year(year):
    return (year % 4 == 0) and (year % 100 != 0) or (year % 400 == 0)

# You should complete the definition of this function:

def days_in_month(month, year):

    if month in ['September', 'April', 'June', 'November']:
        print 30

    elif month in ['January', 'March', 'May', 'July', 'August','October','December']:
        print 31        

    elif month == 'February' and is_leap_year(year) == True:
        print 29

    elif month == 'February' and is_leap_year(year) == False:
        print 28

    else:
        return None

​

​

​

Upvotes: 3

Views: 46016

Answers (6)

kibandi
kibandi

Reputation: 1

*# Write a function that determines how many days there are in a particular month.

Your function will have two parameters: The month as an integer between 1 and 12,

and the year as a four digit integer.

Ensure that your function reports the correct number of days in February for leap years.*

def year():
  a = int(input("insert your year"))
  def month():
    z = int(input("enter month 1-12 "))
    if z==9 or z==4 or z ==6 or z==11:
      return print(30)
    elif z==1 or z==3 or z==5 or z==7 or z==10 or z==12:
      return print(31)
    elif z ==2 and a % 4==0:
      return print("29 its a leap year")
    elif z ==2 and a % 4==1:
      return print(28)   
    
  month()
year()

Upvotes: 0

user14008529
user14008529

Reputation: 1

month=input("month")
year=int(input("year"))
if year%4==0:
        year=('leap year')
if month in ['September', 'April', 'June', 'November']:
        print ("30")

elif month in ['January', 'March', 'May', 'July', 'August','October','December']:
        print ("31")        

elif month == 'February' and year == "leap year":
        print ("29")

elif month == 'February' and  year != "leap year":
        print ("28")

else:
    print("none")

Upvotes: 0

Raunaq
Raunaq

Reputation: 1

month = int (input ('month (1-12): '))

if month < 13:
    if month == 2:
        year = int (input ('year: '))
        if year % 4 == 0:
            if year % 100 == 0:
                if year % 400 == 0:
                    print ('29')
                else:
                    print ('28')
            else:
                print ('29')
        else:
            print ('28')

    elif month >= 8:
        if month % 2 == 0:
            print ('31')
        else:
            print ('30')

    elif month % 2 == 0:
        print ('30')
    else:
        print ('31')

else:
    print ('Only 1-12 accepted')

Upvotes: 0

punit tiwari
punit tiwari

Reputation: 1

"""
Takes the year and month as input and returns the no. of days
"""
def is_leap_year (year):
    return (year % 4 == 0) and (year % 100 != 0) or (year % 400 == 0)

def days_in_month(month, year):
    if month == 'September' or month == 'April' or month == 'June' or month == 'November':
        result=30
    elif month == 'January' or month == 'March' or month == 'May' or month== 'July' or month == 'August' or month == 'October'or month== 'December':
        result=31

    elif month == 'February' and output.is_leap_year ==True:
        result=29

    elif month == 'February' and output.is_leap_year == False:
        result=28
    return result

print(is_leap_year(2016))
print(days_in_month('September',2016))

Upvotes: 0

David.Zheng
David.Zheng

Reputation: 913

Some syntax error in your code:

  1. There should be no space before def days_in_month(month,year). Python use indentation to separate code blocks. This is the error you given in comment.
  2. There is no elseif in python, it should be elif
  3. output.is_leap_year = True, it should be is_leap_year(year) == True. The False part should be changed too.

  4. after if statement and else there should be a :, like

    if month == 'September' or month == 'April' or month == 'June' or month == 'November':
    print 30
elif month == 'January' or month == 'March' or month == 'May' or month== 'July' or month == 'August' or month == 'October' or month== 'December':
    print 31
elif month == 'February' and is_leap_year(year) == True:
    print 29
elif month == 'February' and is_leap_year(year) == False:
    print 28
else:
    print 'Blank'

Upvotes: 2

Madison May
Madison May

Reputation: 2753

A more pythonic approach would be to define the mapping in a dictionary, then simply retrieve the values from the dictionary.

Try it out: 

days_in_month_dict = {"January": 31, "February": 28, 
                      "March": 31, "April": 30,
                      "May": 31, "June": 30, 
                      "July": 31, "August": 31,
                      "September": 30, "October": 31,
                      "November": 30, "December": 31}

def is_leap_year(year):
    return (year % 4 == 0) and (year % 100 != 0) or (year % 400 == 0)

def days_in_month(year, month):
    if is_leap_year(year) and month == "February":
        return 28

    try: 
        #attempt to get value from dictionary 
        return days_in_month_dict[month]
    except KeyError:
        #key does not exist, so we caught the error
        return None

Upvotes: 4

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