CODEWITHSUNDEEP
javaandroid
Andre Amaral Braga
Andre Amaral Braga

Reputation: 321

Convert color RGB to HEX (int result)

I've created a method that convert three integer values to an hex value (string), as you can see below (P.S.: it was not been tested yet): 

protected String convertRGBToHex(int r, int g, int b) {

    String rFString, rSString, gFString, gSString, bFString, bSString, result;
    int red, green, blue;
    int rred, rgreen, rblue;

    red = r / 16;
    rred = r % 16;

    if (red == 10) rFString = "A";
    else if (red == 11) rFString = "B";
    else if (red == 12) rFString = "C";
    else if (red == 13) rFString = "D";
    else if (red == 14) rFString = "E";
    else if (red == 15) rFString = "F";
    else rFString = String.valueOf(red);

    if (rred == 10) rSString = "A";
    else if (rred == 11) rSString = "B";
    else if (rred == 12) rSString = "C";
    else if (rred == 13) rSString = "D";
    else if (rred == 14) rSString = "E";
    else if (rred == 15) rSString = "F";
    else rSString = String.valueOf(rred);

    rFString = rFString + rSString;

    green = g / 16;
    rgreen = g % 16;

    if (green == 10) gFString = "A";
    else if (green == 11) gFString = "B";
    else if (green == 12) gFString = "C";
    else if (green == 13) gFString = "D";
    else if (green == 14) gFString = "E";
    else if (green == 15) gFString = "F";
    else gFString = String.valueOf(green);

    if (rgreen == 10) gSString = "A";
    else if (rgreen == 11) gSString = "B";
    else if (rgreen == 12) gSString = "C";
    else if (rgreen == 13) gSString = "D";
    else if (rgreen == 14) gSString = "E";
    else if (rgreen == 15) gSString = "F";
    else gSString = String.valueOf(rgreen);

    gFString = gFString + gSString;

    blue = b / 16;
    rblue = b % 16;

    if (blue == 10) bFString = "A";
    else if (blue == 11) bFString = "B";
    else if (blue == 12) bFString = "C";
    else if (blue == 13) bFString = "D";
    else if (blue == 14) bFString = "E";
    else if (blue == 15) bFString = "F";
    else bFString = String.valueOf(blue);

    if (rblue == 10) bSString = "A";
    else if (rblue == 11) bSString = "B";
    else if (rblue == 12) bSString = "C";
    else if (rblue == 13) bSString = "D";
    else if (rblue == 14) bSString = "E";
    else if (rblue == 15) bSString = "F";
    else bSString = String.valueOf(rblue);

    bFString = bFString + bSString;

    result = "#" + rFString + gFString + bFString;

    return result;

}

My question is: is there a way that I can convert this string result to an int value, that I can use this way: 

view.setBackgroundColor(0xF82619);

Or is ther a way to convert the string to int and than do it (without crash):

view.setBackgroundColor(result);

Thanks!

Upvotes: 1

Views: 3076

Answers (3)

Henry
Henry

Reputation: 43798

To get an integer you can do

int col = (0xff << 24) | ((r&0xff) << 16) | ((g&0xff) << 8) | (b&0xff);

Even easier is:

int col = Color.rgb(r, g, b);

Upvotes: 5

karan421
karan421

Reputation: 863

Instead of converting it to first string and then to hex directly convert it to hex by

  Integer.valueOf(String.valueOf(n), 16);

it would increase performance of your code.

Upvotes: 2

Shobhit Puri
Shobhit Puri

Reputation: 26017

Suppose you string is 

String col = "0xF82619";

try:

view.setBackgroundColor(Color.parseColor(col));

Upvotes: 3

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