Reputation: 2317
I have tuple in Python that looks like this:
tuple = ('sparkbrowser.com', 0, 'http://facebook.com/sparkbrowser', 'Facebook')
and I want to split it, so that I can get every item from tuple independently in order to te able to do something like this:
domain = "sparkbrowser.com"
level = 0
url = "http://facebook.com/sparkbrowser"
text = "Facebook"
or similar to that. My need is to have every item separated. I tried with `.split(",") on tuple but I've gotten an error which says that tuple doesn't have a split option.
Upvotes: 30
Views: 157530
Reputation: 7238
An alternative for this, is to use collections.namedtuple
. It makes accessing the elements of tuples easier.
Demo:
>>> from collections import namedtuple
>>> Website = namedtuple('Website', 'domain level url text')
>>> site1 = Website('sparkbrowser.com', 0, 'http://facebook.com/sparkbrowser', 'Facebook')
>>> site2 = Website('foo.com', 4, 'http://bar.com/sparkbrowser', 'Bar')
>>> site1
Website(domain='sparkbrowser.com', level=0, url='http://facebook.com/sparkbrowser', text='Facebook')
>>> site2
Website(domain='foo.com', level=4, url='http://bar.com/sparkbrowser', text='Bar')
>>> site1.domain
'sparkbrowser.com'
>>> site1.url
'http://facebook.com/sparkbrowser'
>>> site2.level
4
Upvotes: 2
Reputation: 304215
Best not to use tuple
as a variable name.
You might use split(',')
if you had a string like 'sparkbrowser.com,0,http://facebook.com/sparkbrowser,Facebook'
, that you needed to convert to a list. However you already have a tuple, so there is no need here.
If you know you have exactly the right number of components, you can unpack it directly
the_tuple = ('sparkbrowser.com', 0, 'http://facebook.com/sparkbrowser', 'Facebook')
domain, level, url, text = the_tuple
Python3 has powerful unpacking syntax. To get just the domain
and the text
you could use
domain, *rest, text = the_tuple
rest
will contain [0, 'http://facebook.com/sparkbrowser']
Upvotes: 16
Reputation: 2836
>>> domain, level, url, text = ('sparkbrowser.com', 0, 'http://facebook.com/sparkbrowser', 'Facebook')
>>> domain
'sparkbrowser.com'
>>> level
0
>>> url
'http://facebook.com/sparkbrowser'
>>> text
'Facebook'
Upvotes: 5
Reputation: 798746
Python can unpack sequences naturally.
domain, level, url, text = ('sparkbrowser.com', 0, 'http://facebook.com/sparkbrowser', 'Facebook')
Upvotes: 57