CODEWITHSUNDEEP
javaandroidgoogle-maps
Didac Perez Parera
Didac Perez Parera

Reputation: 3824

Determine a reasonable zoom level for Google Maps given location accuracy

I am trying to center a Google Map to the user location while giving a reasonable zoom level taking into account the accuracy of that location. Could anybody describe how should I compute it? Which variables are involved, how do you achieve this?

Upvotes: 7

Views: 3512

Answers (3)

bendytree
bendytree

Reputation: 13619

If you're looking for something simple:

var zoom = Math.min(20, Math.max(1, Math.log2(591657550/accuracy)-2));

Tweak -2 to get the desired zoom.

Checkout this answer for a chart corresponding zoom with accuracy.

Upvotes: 1

Rio Bautista
Rio Bautista

Reputation: 443

Thanks @Simas! I picked up your algo to make this extension to GMSMapView to calculate for the ideal zoomLevel given the accuracy of a CLLocation.

I had to make adjustments to consider devices with Retina displays since each pixel is not exactly the same as 1 point on the screen:

extension GMSMapView {

    func getIdealZoomLevel(usingLocation location:CLLocation)->Float {

        let retinaScale = Double(UIScreen.mainScreen().scale)

        let equatorLength : Double = 40075004 // in meters
        var metersPerPixel = equatorLength / 256
        let accuracy = location.horizontalAccuracy
        // I used height because I'm on landscape, but moving forward I'll have to get the Min of the width and height.
        // I also took only 75% of the height to give it some margin
        let screenWidth : Double = Double( self.frame.size.height) * 0.75

        var display = metersPerPixel * (screenWidth / retinaScale)

        var zoomLevel : Float = 0.0

        while (display > accuracy) {
            metersPerPixel /= 2
            display = metersPerPixel * (screenWidth / retinaScale)
            zoomLevel += 1
        }

        return zoomLevel
    }
}

It's for a Swift project I'm working on and right now, I'm able to display a good proximity enclosing the radius within the given CLLocation.

Hope this helps.

Upvotes: 0

Simas
Simas

Reputation: 44148

What you are looking for is the formula that calculates the zoom level based on the accuracy of the location.

I managed to come up with this formula which (in my tests) worked pretty well.

Formula

This can be simplified (might not seem so) to this:

Simplified/Scarified formula

This scary looking thing is what you want.

EquatorLength is 40,075,004 meters. While the Meters/Pixel can be calculated by diving the diameter of the accuracy circle by the length of the device screen (in pixels).

Here's a sample program that I used to test this formula:

GoogleMap mMap;

@Override
protected void onStart() {
    super.onStart();

    mMap = ((MapFragment)getFragmentManager().findFragmentById(R.id.map)).getMap();

    // Enable user's location layer
    mMap.setMyLocationEnabled(true);

    mMap.setOnMyLocationChangeListener(new GoogleMap.OnMyLocationChangeListener() {
        @Override
        public void onMyLocationChange(Location location) {
            // Location lat-lng
            LatLng loc = new LatLng(location.getLatitude(), location.getLongitude());

            // Location accuracy diameter (in meters)
            float accuracy = location.getAccuracy() * 2;

            // Screen measurements
            DisplayMetrics metrics = new DisplayMetrics();
            getWindowManager().getDefaultDisplay().getMetrics(metrics);
            // Use min(width, height) (to properly fit the screen
            int screenSize = Math.min(metrics.widthPixels, metrics.heightPixels);

            // Equators length
            long equator = 40075004;

            // The meters per pixel required to show the whole area the user might be located in
            double requiredMpp = accuracy/screenSize;

            // Calculate the zoom level
            double zoomLevel = ((Math.log(equator / (256 * requiredMpp))) / Math.log(2)) + 1;

            Log.e(TAG, String.format("Accuracy: %f. Screen Width: %d, Height: %d",
                    accuracy, metrics.widthPixels, metrics.heightPixels));
            Log.e(TAG, String.format("Required M/Px: %f Zoom Level: %f Approx Zoom Level: %d",
                    requiredMpp, zoomLevel, calculateZoomLevel(screenSize, accuracy)));

            // Center to user's position
            mMap.animateCamera(CameraUpdateFactory.newLatLngZoom(loc, (float) zoomLevel));

            // Prevent the camera centering on the user again
            mMap.setOnMyLocationChangeListener(null);
        }
    });

}

private int calculateZoomLevel(int screenWidth, float accuracy) {
    double equatorLength = 40075004; // in meters
    double metersPerPixel = equatorLength / 256;
    int zoomLevel = 1;
    while ((metersPerPixel * (double) screenWidth) > accuracy) {
        metersPerPixel /= 2;
        zoomLevel++;
    }

    return zoomLevel;
}

Few things to note:

  • This answer is based on this and implements it to check the values generated
  • Accuracy is the radius of user's location and according to the docs it can be up to 68% correct.

Any corrections are very welcome.

Upvotes: 12

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