CODEWITHSUNDEEP
pythonpython-3.x
hjames
hjames

Reputation: 449

Open all files in different directory python

I need to open a file from a different directory without using it's path while staying in the current directory.

When I execute the below code:

for file in os.listdir(sub_dir):
    f = open(file, "r")
    lines = f.readlines()
    for line in lines:
        line.replace("dst=", ", ")
        line.replace("proto=", ", ")
        line.replace("dpt=", ", ")

I get the error message FileNotFoundError: [Errno 2] No such file or directory: because it's in a sub directory.

Question: Is there an os command I can use that will locate and open the file in sub_dir?

Thanks! -let me know if this is a repeat, I searched and couldn't find one but may have missed it.

Upvotes: 9

Views: 40306

Answers (3)

Rahul Telgote
Rahul Telgote

Reputation: 174

Code to copy files using shutil

import shutil
import os

source_dir = "D:\\StackOverFlow\\datasets"
dest_dir = "D:\\StackOverFlow\\test_datasets"
files = os.listdir("D:\\StackOverFlow\\datasets")

if not os.path.exists(dest_dir):
    os.makedirs(dest_dir)

for filename in files:
    if file.endswith(".txt"):
        shutil.copy(os.path.join(source_dir, filename), dest_dir)

print os.listdir(dest_dir)

Upvotes: -1

Saullo G. P. Castro
Saullo G. P. Castro

Reputation: 58885

You must give the full path if those files are not in the current directory:

f = open( os.path.join(sub_dir, file) )

I would not use file as a variable name, maybe filename, since this is used to create a file object in Python.

Upvotes: 11

Martijn Pieters
Martijn Pieters

Reputation: 1121416

os.listdir() lists only the filename without a path. Prepend these with sub_dir again:

for filename in os.listdir(sub_dir):
    f = open(os.path.join(sub_dir, filename), "r")

If all you are doing is loop over the lines from the file, just loop over the file itself; using with makes sure that the file is closed for you when done too. Last but not least, str.replace() returns the new string value, not change the value itself, so you need to store that return value:

for filename in os.listdir(sub_dir):
    with open(os.path.join(sub_dir, filename), "r") as f:
        for line in f:
            line = line.replace("dst=", ", ")
            line = line.replace("proto=", ", ")
            line = line.replace("dpt=", ", ")

Upvotes: 13

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