CODEWITHSUNDEEP
regex
brianrhea
brianrhea

Reputation: 3724

Regex: Find four tabs, but then select the first { prior to the tabs

I'm pretty close to what I need with this rubular:

http://rubular.com/r/tAzRj1H1z7

But, rather than selecting the whole block of which the lines are all indented with 4 tabs, I want to match the { that appears before the block.

Basically, this will allow me to search my codebase to find how many occurences of 4-tab blocks I have, rather than how many lines of 4-tab code.

/\t{4}.+/

.progressBar{
    .progressBarRow {
        .progressBarContainer {
            .progress {
                filter: none;
                -webkit-box-shadow: none;
                -moz-box-shadow: none;
                box-shadow: none;
                border: #b9b9b9 1px solid;
                height:40px;
            }
        }
    }
}

Upvotes: 3

Views: 150

Answers (2)

jaeheung
jaeheung

Reputation: 1208

\{(?=\s*\n\t{4}(?!\t))

Without (?!\t), you're counting 5 or more tabs blocks also.

Upvotes: 0

Cameron
Cameron

Reputation: 98826

You can reverse the question: Find the first { that is followed by a line with four (or more) leading tabs. This regex does the trick:

\{\s*\n\t{4,}

If for whatever reason you really only want to match the { itself, you can either put it in a group:

(\{)\s*\n\t{4,}

or use a look-ahead to make the whole match only {:

\{(?=\s*\n\t{4,})

Upvotes: 1

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