CODEWITHSUNDEEP
c++
Mars
Mars

Reputation: 4995

Checking if a char is a newline

I'm doing an exercise in C++ Primer and basically I am using a switch statement to count the number of vowels in a text that I input.

I input the text using a while loop.

while(cin >> ch)

and proceed with the cases, a, e, i, o, u, incrementing an integer variable for the respective cases. Now the next part of the question says also count the spaces, tabs and newlines.

I tried doing

case ' ':

and so forth using '\t' and '\n'. But it seems like it doesn't compute these cases. I also tried just using a default and using an if else statement

default:
    if(ch == ' ')
        ++space;

etc. But this doesn't proceed either. I also tried putting in the integer values of ' ', '\t', '\n'. What am I doing wrong here? Also, I know that if I use isspace() I can count the combined total but I need to compute each one individually. I'm not sure why the equality test won't do the job.

Upvotes: 6

Views: 4142

Answers (2)

atoMerz
atoMerz

Reputation: 7672

As said by Dietmar, white spaces are skipped by default. You could use cin.getline() to provide your own string delimiter instead of white space characters. I would say this is a generally easier way of reading input compared to using cin.get().

Upvotes: 1

Dietmar Kühl
Dietmar Kühl

Reputation: 153810

By default, formatted input from streams skips leading whitespace. You need to either disable skipping of leading whitespaces or use one of the functions which won't skip spaces:

std::cin >> std::noskipws; // disables skipping of leading whitespace
char c;
while (std::cin.get(c)) {  // doesn't skip whitespace anyway
   ...
}

Upvotes: 12

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