CODEWITHSUNDEEP
phpjqueryjson
chowwy
chowwy

Reputation: 1126

convert php array into single JSON object

I converted a PHP array into JSON, using json_encode. I checked the console, and the objects are displaying in array, but as individual objects.

 [ { Object { 03-13-2012="Jazz"}, Object { 07-19-2012="Pop"}, ... ]

How can I convert this array into one object, like this (in PHP or jQuery):

Object { 03-13-2012="Jazz", 07-19-2012="Pop"}

Edit: Here's the beginning of my print_r for the PHP array:

Array
(
    [0] => Array
        (
            [03-13-2012] => Jazz
        )

    [1] => Array
        (
            [07-19-2012] => Pop
        )
)

Upvotes: 12

Views: 55827

Answers (3)

SteAp
SteAp

Reputation: 11999

In general, you need to prepare such a PHP array, which then should be json_encode and passed along to the server:

$data = array(

  '03-13-2012' => 'Jazz',
  '07-19-2012' => 'Pop',

);

echo json_encode( $data );
exit;

Upvotes: 7

Baba
Baba

Reputation: 95121

Don't be afraid of loops 

$output = array();
foreach($data as $v) {
    $output[key($v)] = current($v);
}
echo json_encode($output, 128);

See Live Demo

Upvotes: 24

manchicken
manchicken

Reputation: 155

You'll want to iterate over the indexed array making the keys of an associative array found therein into keys in a second associative array.

Assumption: You're starting with a JSON string, and you want to end up with a JSON string.

Warning: If you encounter duplicates you will overwrite.

Here's an example of what I'm talking about:

<?php
$foo = json_decode('[{"abc":"A123"},{"xyz":"B234"}]');
$bar = array();
foreach ($foo as $f) {
        foreach ($f as $k => $v) {
                $bar[$k] = $v;
        }
}

echo json_encode($foo)."\n";
echo json_encode($bar)."\n";
?>

Upvotes: 1

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