CODEWITHSUNDEEP
pythondjangojsondjango-queryset
user1500727
user1500727

Reputation:

appending foreign key reference in django json response

during appending the result (appending foreign key ) causes key error

models.py

class table1
    id = models.IntegerField( primary key=TRUE)
    ref = models.ForeignKey('table2')

class table2
    name = models.CharField()
    id = models.IntegerField(primaryKey= True)
    address = models.CharField()

views.py

def relation(request)
"""
    some stuff
"""
    query = "query set makes object of table 1"

    result['content'].append([query['ref__address'])

the error is 

Keyerror at /url
ref__address

Upvotes: 0

Views: 432

Answers (1)

Will Farley
Will Farley

Reputation: 680

def relation(request, pk):
    item = get_object_or_404(Table1, pk=pk)
    context= {'content': item}
    return render(request, 'table1/relation.html', context)

urlpatterns = patterns('',
    url(r'^table1/(?P<pk>\d+)/$', relation, name='relation'),
)

Your problem seems to be that none of your python was valid.

Upvotes: 1

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