Reputation: 571
I created a program that asks the user for a word and then it arranges the letters in that word in alphabetical order and stores it in another string.
#include <stdio.h>
main()
{
char in[100],out[100],ch;
int i,len,j=0;
//ask user for a word
printf("Enter a word: ");
scanf("%s",in);
//arrange that word in alphabetical order
for(ch = 'a'; ch <= 'z'; ++ch)
for(i = 0; i < strlen(in); ++i)
if(in[i] == ch)
{
out[j] = ch;
++j;
}
//print the word
printf("%s",out);
fflush(stdin);
getchar();
}
The problem is when word is stored in the other string, there are some extra letters or symbols after that word. Can someone please tell me what could be possibly wrong with my code?
Upvotes: 3
Views: 1683
Reputation: 47814
C strings are null terminated
Use
out[j] ='\0';
before printf
The %s
specifier searches for a null termination.
In your case it keeps on printing until it finds one, so you get some random symbols.
Also avoid use of fflush
.
You might want to update your logic to sort uppercase characters too.
You might want to use a sort say bubble sort
l=strlen(in);
for(i = 0; i < l; i++)
{
for(j = i + 1; j < l - 1; j++)
if(in[j-1] > in[j]){
ch = in[j];
in[j] = in[j-1];
in[j-1] = ch;
}
}
printf("Sorted String :%s",in);
Upvotes: 3
Reputation: 28131
You're not null terminating the output string. printf("%s",out);
will keep outputting characters until it finds 0 ('\0'
). There are many options to fix this:
terminate the output to the current iterator position after the for-loop:
out[j] = '\0';
make the output the same length as the input:
out[strlen(in)] = '\0';
declare a 0-initialized array:
char out[100] = { 0 };
fill the output array with zero's yourself:
memset(out, 0; sizeof(out));
...
As the sorting is concerned, if it's just for learning then it's fine, otherwise you should pick a more efficient sorting algorithm
Upvotes: 4