CODEWITHSUNDEEP
loopsawk
Josh H
Josh H

Reputation: 83

AWK split files into smaller files on pattern

I have a file similar to:

ISA.00. <rest of line>
information lines
information lines
...
...
...
ISA.00. <rest of line>
information lines
information lines
...
...
ISA.00. <rest of line>

I am using:

awk "/ISA.00./{file=(FILENAME)(++i)}{print > file}" %LOCATION%\%CURRFILE%

To loop through a folder of files, splitting them into files containing one "ISA" data set only. I want to keep the original source file name and add 1 to the end like subfile1, subfile2, subfile3. I have accomplished both.

How would I define an output directory, where the "subfiles" would go, leaving the original source file in the original location, and only having the "subfiles" in the "subfile directory".

I have run into a variety of dead ends and am asking for help as a last resort.

Thank you in advance!

Upvotes: 4

Views: 627

Answers (1)

user000001
user000001

Reputation: 33327

Add the directory name before the filename:

print > "subfiles/"file

If you are on windows, you should use the backslash \ to separate the directory, like this:

print > "subfiles\\"file

(The backslash should be escaped)

This assumes that the directory already exists. Also, use single quotes when with awk, like awk 'commands' file

Upvotes: 1

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