Reputation: 2974
I have two lists:
var_a = [1,2,3,4]
var_b = [6,7]
I want to have a list of dicts as follows:
result = [{'a':1,'b':6},{'a':1,'b':7},{'a':2,'b':6},{'a':2,'b':7},....]
I think the result should be clear.
Upvotes: 0
Views: 2067
Reputation: 18521
from itertools import product
a = [1,2,3,4]
b = [6,7]
[dict(zip(('a','b'), (i,j))) for i,j in product(a,b)]
yields
[{'a': 1, 'b': 6},
{'a': 1, 'b': 7},
{'a': 2, 'b': 6},
{'a': 2, 'b': 7},
{'a': 3, 'b': 6},
{'a': 3, 'b': 7},
{'a': 4, 'b': 6},
{'a': 4, 'b': 7}]
Upvotes: 4
Reputation: 34493
If the name of variables is given to you, you could use.
>>> a = [1,2,3,4]
>>> b = [6,7]
>>> from itertools import product
>>> nameTup = ('a', 'b')
>>> [dict(zip(nameTup, elem)) for elem in product(a, b)]
[{'a': 1, 'b': 6}, {'a': 1, 'b': 7}, {'a': 2, 'b': 6}, {'a': 2, 'b': 7}, {'a': 3, 'b': 6}, {'a': 3, 'b': 7}, {'a': 4, 'b': 6}, {'a': 4, 'b': 7}]
Upvotes: 1
Reputation: 113945
[{k:v for k,v in itertools.izip('ab', comb)} for comb in itertools.product([1,2,3,4], [6,7])]
>>> import itertools
>>> [{k:v for k,v in itertools.izip('ab', comb)} for comb in itertools.product([
1,2,3,4], [6,7])]
[{'a': 1, 'b': 6}, {'a': 1, 'b': 7}, {'a': 2, 'b': 6}, {'a': 2, 'b': 7}, {'a': 3
, 'b': 6}, {'a': 3, 'b': 7}, {'a': 4, 'b': 6}, {'a': 4, 'b': 7}]
Upvotes: 5