Reputation: 39
I am extremely new to java and am very close to finishing a project I have been trying to finish for a long time. Whenever I try to run the code. It gives a null pointer exception as soon as the constructer is called. My code is listed below and any help would be appreciated.
Main class:
import java.util.Scanner;
public class Main
{
public static void main(String[] args)
{
Scanner Input = new Scanner(System.in);
System.out.println("Enter the number of employees to register.");
int arraySize = Input.nextInt();
Input.nextLine();
Employee employee = new Employee(arraySize);
String namesTemp;
String streetTemp;
String cityTemp;
String stateTemp;
String zipCodeTemp;
String dateOfHireTemp;
for(int x = 0; x < arraySize; x++)
{
System.out.println("Please enter the name of Employee " + (x + 1));
namesTemp = Input.nextLine();
System.out.println("Please enter the street for Employee " + (x + 1));
streetTemp = Input.nextLine();
System.out.println("Please enter the city of Employee " + (x + 1));
cityTemp = Input.nextLine();
System.out.println("Please enter the state of Employee " + (x + 1));
stateTemp = Input.nextLine();
System.out.println("Please enter the zip code of Employee " + (x + 1));
zipCodeTemp = Input.nextLine();
System.out.println("Please enter the date of hire for Employee " + (x + 1));
dateOfHireTemp = Input.nextLine();
employee.addEmployee(x, namesTemp, streetTemp, cityTemp, stateTemp, zipCodeTemp, dateOfHireTemp);
System.out.println("The employee ID for employee " + (x + 1) + " is " + (x + 1));
}
for(int x = 0; x < arraySize; x++)
{
String info[] = employee.getEmployeeInfo(x);
System.out.println("Employee ID: " + (x + 1));
System.out.println("Name: " + info[0]);
System.out.println("Address: " + info[1]);
System.out.println("Date of Hire: " + info[2]);
}
}
}
Employee class:
public class Employee
{
private EmployeeName name;
private EmployeeAddress address;
private EmployeeDateOfHire hireDate;
public Employee(int arraySize)
{
}
public void addEmployee(int x, String name, String street, String city, String state, String zipCode, String hireDate)
{
this.name.setName(x, name);
this.address.setAddress(x, street, city, state, zipCode);
this.hireDate.addDateOfHire(x, hireDate);
}
public String[] getEmployeeInfo(int x)
{
String info[] = new String[3];
info[0] = name.getName(x);
info[1] = address.getAddress(x);
info[2] = hireDate.getDateOfHire(x);
return info;
}
}
EDIT--
Here is how I wrote my data classes. They are all written in the same format.
Name Class:
public class EmployeeName
{
private String names[];
public void setArray(int x)
{
String array[] = new String[x];
this.names = array;
}
public void setName(int x, String name)
{
this.names[x] = name;
}
public String getName(int x)
{
return this.names[x];
}
}
Upvotes: 1
Views: 2170
Reputation: 279910
In the addEmployee()
method
public void addEmployee(int x, String name, String street, String city, String state, String zipCode, String hireDate)
this.name.setName(x, name);
this.address.setAddress(x, street, city, state, zipCode);
this.hireDate.addDateOfHire(x, hireDate);
}
you haven't initialized name
or the other fields. By default, instance fields will be initialized to null
. Trying to dereference null
will cause a NullPointerException
.
You should initialize those fields, for example in your Constructor
public Employee(int arraySize)
{
this.name = new EmployeeName();
this.address = new EmployeeAddress();
this.hireDate = new EmployeeDateOfHire();
}
I don't know what those classes look like.
Seeing
private String names[];
public void setArray(int x)
{
String array[] = new String[x];
this.names = array;
}
public void setName(int x, String name)
{
this.names[x] = name;
}
You call setName()
which would also throw a NullPointerException
because you're trying to dereference names
but it's null
. You would have to call setArray()
first but then that would fail too because if x
is 0, you will create an array of size 0 but then try to access the element at index 0, which would not exist. If x
was 1, you would create array of size 1 but try to access the element at index 1
(second element), which would throw an IndexOutOfBoundsException
.
Seriously rethink your design. Why is this EmployeeName
class so complicated? Why don't you just have a String field name
. Or two fields, firstName
and lastName
?
Upvotes: 3