CODEWITHSUNDEEP
batch-file
user1151923
user1151923

Reputation: 1872

Invalid number error when setting variable

I am using the code from this thread to get tomorrow's date. It is as follows:

@echo off

set /a d=%date:~0,2%
set /a m=%date:~3,2%
set /a y=%date:~6,4%

:loop
  set /a d+=1

  if %d% gtr 31 (
    set d=1
    set /a m+=1

    if %m% gtr 12 (
      set m=1
      set /a y+=1
    )
  )
xcopy /d:%m%-%d%-%y% /l . .. >nul 2>&1 || goto loop

echo %d%/%m%/%y%

However I am getting the following error:

Invalid number. Numeric constants are either decimal (17), hexadecimal (0x11), or octal (021).

Although the in the post's text it says:

When assigning values to variables, we use using SET /A (rather than just SET) to overcome the problem of attempting to perform octal arithmetic on '08' and '09' later on. This is because leading zeros are trimmed off during arithmetic assignment.

Upvotes: 0

Views: 3531

Answers (1)

Endoro
Endoro

Reputation: 37579

assuming, you have leading zeros in day and month:

set /a d=1%date:~0,2%-100
set /a m=1%date:~3,2%-100
set /a y=%date:~6,4%

Upvotes: 7

Related Questions