CODEWITHSUNDEEP
pythonfilepython-3.xfile-io
Bython
Bython

Reputation: 1145

Error when creating a new text file with python?

This function doesn't work and raises an error. Do I need to change any arguments or parameters? 

import sys

def write():
    print('Creating new text file') 

    name = input('Enter name of text file: ')+'.txt'  # Name of text file coerced with +.txt

    try:
        file = open(name,'r+')   # Trying to create a new file or open one
        file.close()

    except:
        print('Something went wrong! Can\'t tell what?')
        sys.exit(0) # quit Python

write()

Upvotes: 69

Views: 273217

Answers (7)

prathima
prathima

Reputation: 113

following script will use to create any kind of file, with user input as extension

import sys
def create():
    print("creating new  file")
    name=raw_input ("enter the name of file:")
    extension=raw_input ("enter extension of file:")
    try:
        name=name+"."+extension
        file=open(name,'a')

        file.close()
    except:
            print("error occured")
            sys.exit(0)

create()

Upvotes: 6

user3725107
user3725107

Reputation: 33

You can use open(name, 'a')

However, when you enter filename, use inverted commas on both sides, otherwise ".txt"cannot be added to filename

Upvotes: 0

user5449023
user5449023

Reputation:

You can os.system function for simplicity :

import os
os.system("touch filename.extension")

This invokes system terminal to accomplish the task.

Upvotes: 1

Daphnne
Daphnne

Reputation: 116

import sys

def write():
    print('Creating new text file') 

    name = raw_input('Enter name of text file: ')+'.txt'  # Name of text file coerced with +.txt

    try:
        file = open(name,'a')   # Trying to create a new file or open one
        file.close()

    except:
        print('Something went wrong! Can\'t tell what?')
        sys.exit(0) # quit Python

write()

this will work promise :)

Upvotes: 1

SriSreedhar
SriSreedhar

Reputation: 427

instead of using try-except blocks, you could use, if else

this will not execute if the file is non-existent, open(name,'r+')

if os.path.exists('location\filename.txt'):
    print "File exists"

else:
   open("location\filename.txt", 'w')

'w' creates a file if its non-exis

Upvotes: 6

Ivan
Ivan

Reputation: 63

This works just fine, but instead of 

name = input('Enter name of text file: ')+'.txt'

you should use

name = raw_input('Enter name of text file: ')+'.txt'

along with

open(name,'a') or open(name,'w')

Upvotes: 3

falsetru
falsetru

Reputation: 369444

If the file does not exists, open(name,'r+') will fail.

You can use open(name, 'w'), which creates the file if the file does not exist, but it will truncate the existing file.

Alternatively, you can use open(name, 'a'); this will create the file if the file does not exist, but will not truncate the existing file.

Upvotes: 114

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