CODEWITHSUNDEEP
javascript
mandel99
mandel99

Reputation: 124

Get only first match in if

"if" gives me more answers.. How to get only first? Thanks people. http://jsfiddle.net/TsxBy/

var content = "var=xyz-id=2,var=abc-id=1,var=bcd-id=7,var=abc-id=1,var=hij-id=4,var=xyz-id=2";
content = content.split(',');
for (i = 0; i < content.length; i++) {
    var temp = content[i].match(/\d/);
    if (temp == '1') {
        alert('match 1'); // how to response only first "matched"?
    }
    if (temp == '2') {
        alert('match 2'); // same here
    }
}

Upvotes: 0

Views: 124

Answers (2)

rgin
rgin

Reputation: 2311

I think I understand your issue a bit. Please check this fiddle update if it's what you need. 

var content = "var=xyz-id=2,var=abc-id=1,var=bcd-id=7,var=abc-id=1,var=hij-id=4,var=xyz-id=2";

content = content.split(',');
var ctr1 = 0, ctr2 = 0;

for (i = 0; i < content.length; i++) { 

    var temp = content[i].match(/\d/);
    console.log(temp[0]);

    if (temp[0] == '1' && ctr1 == 0) {
        alert('match 1');
        ctr1++;
    }
    if (temp[0] == '2' && ctr2 == 0) {
        alert('match 2');
        ctr2++;
    } 
}

Upvotes: 2

Atrum
Atrum

Reputation: 76

Your code is checking for a single integer in each element of the array, resulting in 6 iterated checks, 4 of which have a matching number to one of your if statements, which is what you get, 4 alerts.

If you want it to stop looking after it matches the first number, use a break at the end of the desired if statement.

Upvotes: 0

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