Reputation: 171
I have two buttons for a register form.
<input type="submit" name="submit1" value="Pay Now" class="submit" id="submit1" />
<input type="submit" name="submit2" value="Pay Later" class="submit" id="submit2" />
Check to see if either button is pushed
if((isset($_POST['submit1'])) or (isset($_POST['submit2'])))
Then PHP code to sanitize and validate data for either input
Now I want to have the "Pay Now" go to one page, and the "Pay Later" go to a different page, but I can n not figure it out. Thanks
Upvotes: 0
Views: 1182
Reputation: 14523
Use form action like this:
<form action="" method="post">
<input type="submit" name="submit1" value="Pay Now" class="submit" id="submit1" onclick="this.form.action='page1.php'" />
<input type="submit" name="submit2" value="Pay Later" class="submit" id="submit2" onclick="this.form.action='page2.php'" />
</form>
Upvotes: 2
Reputation: 10717
You can use $_SESSION
. After set session, redirect page and get session data
if(isset($_POST['submit1']) || isset($_POST['submit2'])) {
$_SESSION['post'] = $_POST;
if($_POST['submit1'])
header("Location: pay_now.php");
elseif($_POST['submit2'])
header("Location: pay_later.php");
}
$data = $_SESSION['post'];
Upvotes: 2
Reputation: 9765
You can do it in PHP but you can also do it in JS using onlick event.
<form method="POST" action="" name="dynamicForm">
<input type="button" name="submit" value="Pay Now" class="submit" id="submit1" onclick="buttonClicked(1);" />
<input type="button" name="submit" value="Pay Later" class="submit" id="submit2" onclick="buttonClicked(2);" />
</form>
<script type="text/javascript">
function buttonClicked(type) {
if (type === 1) {
document.dynamicForm.action = 'firstUrl';
} else {
document.dynamicForm.action = 'secondUrl';
}
document.dynamicForm.submit();
}
</script>
Upvotes: 0
Reputation: 4620
Try this
if(isset($_POST['submit']))
{
if($_POST['submit'] == 'Pay Now')
{
echo $_POST['submit'];
}
if($_POST['submit'] == 'Pay Later')
{
echo $_POST['submit']
}
}
Upvotes: 0