CODEWITHSUNDEEP
c
Robert Aleksander Yevdokimov
Robert Aleksander Yevdokimov

Reputation: 37

invalid type argument of unary '*'

I'm a week into an intro programming class, and I'm having trouble with fixing what's supposed to be a relatively simple code. I keep getting an invalid type argument of unary '*' error. 

#include <stdio.h>
#define PI 3.14159; 
int main()
{
   float r;
   float area;
   scanf("%f", &r);
   area = PI * r * r;
   printf("Area is %f", area);
   return 0; 
}

Could someone explain this, and how to fix it?

Upvotes: 2

Views: 1911

Answers (2)

rems4e
rems4e

Reputation: 3172

You have to remove the extra ; in the definition of the macro PI. It is unnecessary for macro, and in your case results in syntax error after expansion.

Upvotes: 2

cnicutar
cnicutar

Reputation: 182744

#define PI 3.14159; 
                  ^

Drop the semicolon. Leaving it in, the code will expand to:

area = 3.14159; * r * r;

Upvotes: 10

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