Reputation: 85
My compiler raises the warning #381-D: extra ";" ignored
in such a situation:
I have a struct defined, like the following
struct example_s
{
u8_t foo;
SOME_MACRO(bar);
};
The macro SOME_MACRO(x)
does the following:
#if defined(SYSTEM_A)
#define SOME_MACRO(x) u16_t x##something
#else
#define SOME_MACRO(x) /* nothing */
#endif
Of course, the warning is correct, when SYSTEM_A
is not defined. Simply because I have now a ;
within the struct. But does someone know a way to avoid it correctly? I don't want to break the typical C-style by moving the ;
into the macro.
Upvotes: 4
Views: 832
Reputation: 15954
You can add an unnamed 0-width bitfield instead:
#if defined(SYSTEM_A)
#define SOME_MACRO(x) u16_t x##something
#else
#define SOME_MACRO(x) unsigned :0
#endif
Upvotes: 3
Reputation: 2558
you can also insert an empty anonymous struct :
#if defined(SYSTEM_A)
#define SOME_MACRO(x) u16_t x##something
#else
#define SOME_MACRO(x) struct {}
#endif
Upvotes: 3
Reputation: 212959
One way that is a bit of a kludge but it seems to work with gcc:
#if defined(SYSTEM_A)
#define SOME_MACRO(x) u16_t x##something
#else
#define SOME_MACRO(x) int x[0] /* nothing */
#endif
With this method you end up with a struct like this:
struct example_s
{
u8_t foo;
int bar[0];
};
which has the correct size (i.e. as size as if bar
had not been defined at all).
Upvotes: 4