CODEWITHSUNDEEP
phpmysqlpaginationlaravellaravel-4
Daniel Twigg
Daniel Twigg

Reputation: 759

Pagination not working in Laravel 4

I am trying to use pagination in Laravel 4 with quite a complex query (using Fluent query builder I think).

Query SQL Code

SELECT `description`, `email`, `website`, `telephone`, `purpose`, `services`,      
       `eligibilitycriteria`, `meetingplace`, `servicecosts`, `area`, 
       `servicetype`, `beneficiarytype`, `charitynumber`, `address`, `contacts`, 
MATCH (
       `name`,`description`,`email`,`website`,`telephone`,`purpose`,`services`,
       `eligibilitycriteria`,`meetingplace`,`servicecosts`,`area`,`servicetype`,
       `beneficiarytype`,`charitynumber`,`address`,`contacts`
      ) 
AGAINST ("dan") AS Score0, 
MATCH (`name`) AGAINST ("dan") AS Score1 FROM `directory_cache`   
WHERE MATCH(
       `description`,`email`,`website`,`telephone`,`purpose`,`services`,
       `eligibilitycriteria`,`meetingplace`,`servicecosts`,`area`,`servicetype`,
       `beneficiarytype`,`charitynumber`,`address`,`contacts`
      ) 
AGAINST ("dan") 
ORDER BY (Score0*1 + Score1*1.5) DESC

I am calling the paginate at the end of the query builder in my controller like follows: 

$results = $query->paginate(20);

Then in my view I simply call $results->links and I do get the pagination buttons for next page and the numbered pages etc.

But when I click on Page 2, this is where I encounter the problem.

My form uses POST to submit the search form. Both the get and post actions use the same view file to display the search form and results.

Please help and if you need any more information I am happy to edit the post and add it in, I am here all night!

Upvotes: 1

Views: 2145

Answers (2)

Abishek
Abishek

Reputation: 11691

My suggestion would be to route both viewResults and search to the same route using Route::any() so that you would need to perform seperate functionality for both actions

routes.php

Route::any('/list','Controller@viewResults');

Controller.php

function viewResults(){

    $searchQuery = Input::get('searchQuery');
    if(isset($searchQuery))
       $query = DirectoryCache::where(...)->where(...);
    else
       $query = DirectoryCache::where(1, '=', 1);

    $results = $query->paginate();

    //This will append the searchQuery to your pagination links
    $results->appends(array('searchQuery'=>$searchQuery));
}

So irrespective of you perform a POST or GET you would execute the same action and still be able to perform search and get the results. I hope this helps

Upvotes: 4

Sergiu Paraschiv
Sergiu Paraschiv

Reputation: 10153

You'll have to use GET or store the query in session, I don't see an easier way of doing this. Using POST like you do is bad practice anyway. You shoud POST and then redirect from there, either passing GET parameters or keeping the query in session.

function post_search() {
    $query = DirectoryCache::where(...)->where(...);
    Session::put('searchQuery', $query);

    return Redirect::to_action('controller@viewResults');
}

function get_viewResults($page = 1) {
    $perPage = 20;

    $query = Session::get('searchQuery', DirectoryCache::where(1, '=', 1));
    $query = $query->paginate();
    $query->skip($page * $perPage)->take($perPage);

    $results = $query->get(); 
    ...
}

I know it's Laravel 3, I haven't touched 4 yet, but the APIs should be almost the same.

Upvotes: 0

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