CODEWITHSUNDEEP
phpradio-button
Newb
Newb

Reputation: 678

PHP syntax and structure for radio button and its values

Radio box code:

<input
  type  = "radio"
  name  = "choice"
  value = "A" />Apples />

<input
  type  = "radio"
  name  = "choice"
  value = "B" />Oranges<br />

$choice=array("A"=>1.00, "B"=>0.80);
echo $choice["A"]; // will give me the value of 1.00
echo $choice["B"]; // will give me the value of 0.80

Given the code snippet above, is there anything wrong in terms of either the HTML radio box, the array or the choices?

Upvotes: 0

Views: 2539

Answers (3)

Ondrej Slint&#225;k
Ondrej Slint&#225;k

Reputation: 31910

I'm not sure what are you trying to achieve, but there are several things that need your attention.

First of all, check the syntax of <input>: http://www.w3schools.com/html/html_forms.asp

So I'd change your html code to:

<form ... >
<input type="radio" name="choice" value="1.00" /> Apples
<br />
<input type="radio" name="choice" value="0.80" /> Oranges
</form>

And on server side, after actually submitting the form, just look for $_POST[ "choice" ] for your desired value (1.00 or 0.80).

Upvotes: 0

Sarfraz
Sarfraz

Reputation: 382696

As far as i understood your question, PHP Code seems to be wrong. You have not specified an array in your html code which is done using [ ].

This is what you do in you php code to echo the selection of the radio:

echo $_REQUEST['choice'];

This will echo selected radio buttons value either A or B.

Upvotes: 1

Atli
Atli

Reputation: 7930

Nope, that looks perfectly fine.
Except for the random /> after your Apples text, but I suspect this is a typo?

You may also want to consider this. Probably what you are heading towards? :)

<?php
$choices = array("A"=>1.00, "B"=>0.80);
if(in_array($_REQUEST['choice'], array_keys($choices))) {
    echo $choices[$_REQUEST['choice']];
}
else {
    echo "Invalid choice received!";
}
?>

This would be the code that receives your radio choice. It makes sure the choice is valid and then prints it.

Upvotes: 3

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