Reputation: 1787
I have 2 list object of type of some class,
class person
{
public string id { get; set; }
public string name { get; set; }
}
List<person> pr = new List<person>();
pr.Add(new person { id = "2", name = "rezoan" });
pr.Add(new person { id = "5", name = "marman" });
pr.Add(new person { id = "3", name = "prithibi" });
List<person> tem = new List<person>();
tem.Add(new person { id = "1", name = "rezoan" });
tem.Add(new person { id = "2", name = "marman" });
tem.Add(new person { id = "1", name = "reja" });
tem.Add(new person { id = "3", name = "prithibi" });
tem.Add(new person { id = "3", name = "prithibi" });
Now i have to get all the ids from "pr" ListObject that has no entry or odd number of entries in the "tem" ListObejct. using lamda.
To do this i have used,
HashSet<string> inconsistantIDs = new HashSet<string>(pr.Select(p => p.id).Where(p => tem.FindAll(t => t.id == p).Count == 0 || tem.FindAll(t => t.id == p).Count % 2 != 0));
and it works fine.
but you can see from the code i have used tem.FindAll(t => t.id == p).Count twice to comapre with ==0 and %2!=0.
Is there any way to use tem.FindAll(t => t.id == p).Count once and save it to a temporary variable and then compare this variable with ==0 and %2!=0.
More simply i just want to use it once for two condition here.
Upvotes: 7
Views: 9749
Reputation: 10427
Use a statement lambda instead of an expression lambda
var inconsistantIDs = new HashSet<string>(
pr.Select(p => p.id).Where(p =>
{
var count = tem.FindAll(t => t.id == p).Count;
return count == 0 || count % 2 != 0;
}
));
Upvotes: 16
Reputation: 7475
Besides statement lambda you can use let clause:
HashSet<string> inconsistantIDs = new HashSet<string>(
from p in pr
let count = tem.FindAll(t => t.id == p).Count
where count == 0 || count % 2 != 0
select p.id
);
Upvotes: 4
Reputation: 51204
On a side note, strictly performance wise, you would get better performance if you created a hash mapping of each ID to its count and then search it in a loop.
Right now you have a O(n*m)
algorithm, which would be reduced to O(n+m)
:
// create a map (id -> count), O(m) operation
var dictionary = new Dictionary<string, int>();
foreach (var p in tem)
{
var counter = 0;
dictionary.TryGetValue(p.id, out counter);
counter++;
dictionary[p.id] = counter;
}
// search the map, O(n) operation
var results = new HashSet<string>();
foreach (var p in pr)
{
var counter = 0;
dictionary.TryGetValue(p.id, out counter);
if (counter == 0 || counter % 2 != 0)
results.Add(p.id);
}
Upvotes: 2
Reputation: 3082
HashSet<string> inconsistantIDs = new HashSet<string>(
pr.Select(p => new { Id = p.id, Cnt = tem.FindAll(t => t.id == p.id).Count() })
.Where(p => p.Cnt == 0 || p.Cnt % 2 != 0)
.Select(p => p.Id);
Upvotes: 2
Reputation: 460028
Perhaps simply:
var query = pr.Where(p => { int c = tem.Count(p2 => p.id == p2.id); return c == 0 || c % 2 != 0; });
returns two persons:
2 "rezoan"
5 "marman"
Upvotes: 4