CODEWITHSUNDEEP
python
Underdog_Nate
Underdog_Nate

Reputation: 15

Python Writing Quadratic Formula

I want to try and make my print function automatically substitute the variable 'a' 'b' and 'c' with one of the values assigned to those variables in my tests. How would I do this? My ideal output would look like this Equation: 1x**2 + 4x + 4 One root. 2.0

import math

def quadraticRoots(a,b,c):
    print('Equation: ax**2 + bx + c')    # (this is what I am trying and it doesn't work)
    discriminant = b**2 - 4 * a * c
    if discriminant > 0:
        root1 = float(-b + math.sqrt(b**2 - 4 * a * c))/ (2 * a)
        root2 = float(-b - math.sqrt(b**2 - 4 * a * c))/ (2 * a)
        print('Two roots.')
        print(root1)
        print(root2)
    elif discriminant == 0:
        root1 = float(-b + math.sqrt(b**2 - 4 * a * c))/ (2 * a)
        print('One root.')
        print(root1)
    elif discriminant < 0:
        print('No roots.')

def test():
    quadraticRoots(1,0,0)
    quadraticRoots(2,-11,-21)
    quadraticRoots(4,1,4)
    quadraticRoots(1,2,8)
    quadraticRoots(3,-11,19)
    quadraticRoots(1,4,4)
    quadraticRoots(16,-11,64)
    quadraticRoots(1,18,81)
    quadraticRoots(1,7,42)
    quadraticRoots(5,10,5)

test()

Upvotes: 1

Views: 3507

Answers (2)

PyNEwbie
PyNEwbie

Reputation: 4940

Are you stating that 

 print('Equation: ax**2 + bx + c')

does not print the equation with values for a , b and c

print ('equation: ' + str(a) + 'x**2 + ' + str(b) + 'x + ' + str(c))

the problem is that you are asking it to print a literal but you want it to print based on your values. CAVEAT I think you must be using a 3+ flavor of python and I work in 2.7

Upvotes: 1

Mihai Maruseac
Mihai Maruseac

Reputation: 21435

Try the following:

print('Equation: {0}x**2 + {1}x + {2}'.format(a,b,c))

Upvotes: 4

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