Reputation: 1994
Apologies for the vague title of this question!
I have the following JS, it looks for img tags with images of certain sources. It then replaces the img tag with a span so that I can replace the images/icons with iconfonts.
var paths = [
"folder%2Fadd",
"folder%2Fclear",
"folder%2Fdelete",
"folder%2Fedit",
"folder%2Fmove",
"folder%2Fsort",
];
var fullPaths = paths.map(function(x) { return "img[src*='" + x + "']"; } );
var imgs = document.querySelectorAll(fullPaths);
for (var i = 0; i < imgs.length; i++) {
var span = document.createElement("span");
span.addClass("iconfont");
span.title = imgs[i].parentNode.title;
imgs[i].parentNode.replaceChild(span, imgs[i]);
}
Everything is working nicely so far, but there is one more issue that I cannot solve.
Apart from adding a class to the span of .iconfont, I also want to add two more classes to the span - 1) the original class of the replaced img element, and 2) the name of the image source as in my array, but without the 'folder/' bit in front.
So, at the moment I have:
<img class = "tinyicon" src="******/t/edit">
and my script creates this in the DOM:
<span class = "iconfont">
But I want my script to create the following:
<span class = "iconfont tinyicon edit">
That is what I am after :)
Thanks for having a look!
Upvotes: 3
Views: 88
Reputation: 388316
var span = document.createElement("span");
var className = "iconfont " + imgs[i].className + ' ' + imgs[i].src.match(/([a-z])$/i, '')
span.className = className ;
span.title = imgs[i].parentNode.title;
imgs[i].parentNode.replaceChild(span, imgs[i]);
Upvotes: 1
Reputation: 707456
Change this:
var span = document.createElement("span");
span.addClass("iconfont");
to this:
var span = document.createElement("span");
span.className = "iconfont tinyicon edit";
Your addClass()
wouldn't work anyway because span is a DOM node, not a jQuery object.
Upvotes: 1
Reputation: 318232
var paths = [
"folder%2Fadd",
"folder%2Fclear",
"folder%2Fdelete",
"folder%2Fedit",
"folder%2Fmove",
"folder%2Fsort",
];
var fullPaths = paths.map(function(x) { return "img[src*='" + x + "']"; } );
var imgs = document.querySelectorAll(fullPaths);
for (var i = 0; i < imgs.length; i++) {
var img = imgs[i],
iClass = img.className,
iSrc = img.src.split('/').pop(),
span = $('<span />', {'class': 'iconfont '+iClass+' '+iSrc,
title : img.parentNode.title
});
$(img).replaceWith(span);
}
Upvotes: 1