CODEWITHSUNDEEP
java
user2731202
user2731202

Reputation: 7

Illegal character error when compiling simple hasse algorithm program in java

I cant seem to figure out why the below code won't compile. I get up an error for the line saying: if ((number % 2) == 0) {. The error message says: "illegal character". The program is supposed to take a number n. If the n == to 1, the program stops. If n is odd it, then the new n == (n*3)+1. If n is even, new n == n/2.

import java.util.Scanner; 
import java.lang.Math.*; 

public class HasseAlgoritme {

public static void main(string [] args) {
 Scanner tastatur = new Scanner(System.in); 

 System.out.print("Input the first starting number"); 
 int number = tastatur.next(); 

 while (number != 1) { 
  System.out.print(number);        
      if ((number % 2) ==  0) {       
        System.out.println(number);
      }          
      else {
        number = (number*3)+1; 
        System.out.print(number); 
      }              
 } 
}}

Upvotes: 0

Views: 516

Answers (6)

upog
upog

Reputation: 5531

this will compile.I have closed the scanner. and You are running infinite while loop

import java.util.Scanner; 

public class HasseAlgoritme {
    public static void main(String [] args) { 
        Scanner tastatur = new Scanner(System.in);
        System.out.print("Input the first starting number"); 
        int number = Integer.valueOf(tastatur.next()); 
        while (number != 1) { 
            System.out.print(number);
            if ((number % 2) ==  0) { 
                System.out.println(number);
            }
            else {
                number = (number*3)+1; 
                System.out.print(number); 
            } 
        } 
        tastatur.close();
    }

}

Upvotes: 0

Maroun
Maroun

Reputation: 95968

public static void main(string[] args)

Should be 

                        ↓
public static void main(String[] args)

Java is case sensitive!

Also number should be String and not an int, this won't compile (or use nextInt instead of next).

Upvotes: 5

sara
sara

Reputation: 3934

Change Scanner.next() to Scanner.nextInt()

Upvotes: 0

Ajinkya
Ajinkya

Reputation: 22720

Also tastatur.next(); returns String, you might want to use tastatur.nextInt(); instead

Upvotes: 0

Kevin Bowersox
Kevin Bowersox

Reputation: 94479

If a number is being entered the scanner should use nextInt()

 int number = tastatur.nextInt();
 tastatur.nextLine();

Upvotes: 0

Vimal Bera
Vimal Bera

Reputation: 10497

Read integer using this : int number = tastatur.nextInt(); or
this : int number = Integer.parseInt(tastatur.next());.

Upvotes: 0

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