CODEWITHSUNDEEP
javaparser
Masud Rahman
Masud Rahman

Reputation: 1062

Handling exception in Javaparser

I am trying to handle the exception produced by Javaparser library due to token error. I used the following code.

String content=getTheSource();
    ByteArrayInputStream bin=new ByteArrayInputStream(content.getBytes());
    try
    {
        CompilationUnit cu=JavaParser.parse(bin);
    } catch (Exception e) {
        // TODO Auto-generated catch block
        //e.printStackTrace();
                    //my handling code here
    }finally{
        bin.close();
    }

However, the exception was never caught and I am getting a different exception generated from somewhere else. I got this exception:

Exception in thread "main" japa.parser.TokenMgrError: Lexical error at line 1, column 16. Encountered: "#" (35), after : "" at japa.parser.ASTParserTokenManager.getNextToken(ASTParserTokenManager.java:2247) at japa.parser.ASTParser.jj_ntk(ASTParser.java:9986) at japa.parser.ASTParser.ClassOrInterfaceBody(ASTParser.java:926) at japa.parser.ASTParser.ClassOrInterfaceDeclaration(ASTParser.java:604) at japa.parser.ASTParser.TypeDeclaration(ASTParser.java:524) at japa.parser.ASTParser.CompilationUnit(ASTParser.java:269) at japa.parser.JavaParser.parse(JavaParser.java:81) at japa.parser.JavaParser.parse(JavaParser.java:94) at misc.CompileTest.main(CompileTest.java:45)

Any idea, how to handle the exception? Thanks in advance

Upvotes: 0

Views: 883

Answers (2)

Danny
Danny

Reputation: 171

From version 3 on, JavaParser will/should not throw this error anymore.

Upvotes: 1

bresai
bresai

Reputation: 377

As the name indicates, TokenMgrError is an error. So you have to catch an Error instead of Exception. If you want to catch both Error and Exception, you can use Throwable instead.

Originally, this error is throwed by JavaCC (TokenMgrError) which is used by Javaparser.

Upvotes: 1

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