Reputation: 438
I am writing a function that makes a http call to a web service, grabs some data and calls another function based on this data. If the service is down, the second function should not be called. I thought the obvious way to do this would be to write $.when(func1()).done(func2);
but this will trigger func2 even when the request is aborted. I realise that I can do a workaround by calling func2 within the success function of func1's $.getJSON
method, but I would like to use the deferred syntax if possible. Can anyone suggest how to handle this in a way that is consistent with the deferred object syntax?
function checker() {
console.log("in checker");
$.getJSON("http://djdjdjdjdjinvalidUrl.dkdkdk", function(data) {
console.log("in success function");
});
}
function crosser(data) {
console.log("in crosser");
}
$(document).ready(function(){
$.when(checker()).done(crosser);
});
See jsFiddle for a live example.
Upvotes: 1
Views: 98
Reputation: 4331
For asynchronous events like $.getJSON
, you need to use the actual deferred object. I've updated your jsfiddle with this object in use: http://jsfiddle.net/wM7aP/1/
Code:
function checker() {
var dfd = new jQuery.Deferred();
console.log("in checker");
$.getJSON("http://djdjdjdjdjinvalidUrl.dkdkdk", function(data) {
//handle data here
dfd.resolve( "hurray" );
});
return dfd.promise();
}
function crosser(data) {
console.log("in crosser");
}
$(document).ready(function(){
$.when(checker()).done(crosser);
});
Upvotes: 0
Reputation: 388316
you need to return a promise from checker
function checker() {
console.log("in checker");
return $.getJSON("http://djdjdjdjdjinvalidUrl.dkdkdk", function(data) {
console.log("in success function");
});
}
Demo: Fiddle
Also there is no need to use $.when()
$(document).ready(function(){
checker().done(crosser);
});
Demo: Fiddle
Upvotes: 7