How to get pid given the process name

Question

Hi I have searched various forums and here as well, I could find some answers for Linux and Mac but not able to find solution for Unix and specially Korn Shell.

How to get process name (command name) from process id (pid)

Below reference I found from Stack Overflow This one And this one also

I tried the below command

ps -eaf | awk '{ print substr($0, index($0, $9)) }'

The above command is failing at a point where TIME is given rather than Month and Date (because in this case there will be only 8 columns in string)

Any suggestion would help.

Answer 1

You can use pidof to get all IDs of running processes with the name p_name:

pidof p_name | tr ' ' '\n' (for a vertical listing)

pkill p_name - kill all processes whith the name p_name

Make sure that you have the permission to kill them all :)

Answer 2

ps -C <the-name> -o etime=

My ps is from procps-ng .

Answer 3

I think it is easier to use pgrep

$ pgrep bluetoothd
441

Otherwise, you can use awk:

ps -ef | awk '$8=="name_of_process" {print $2}'

For example, if ps -efhas a line like:

root       441     1  0 10:02 ?        00:00:00 /usr/sbin/bluetoothd

Then ps -ef | awk '$8=="/usr/sbin/bluetoothd" {print $2}' returns 441.

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In ksh pgrep is not found. and the other solution is failing in case below is output from ps command jaggsmca325 7550 4752 0 Sep 11 pts/44 0:00 sqlplus dummy_user/dummy_password@dummy_schema

Let's check the last column ($NF), no matter its number:

$ ps -ef | awk '$NF=="/usr/sbin/bluetoothd" {print $2}'
441

If you want to match not exact strings, you can use ~ instead:

$ ps -ef | awk '$NF~"bluetooth" {print $2}'
441
1906

Answer 4

If your ps | awk solution is failing because the output of ps is not what you want, then make it so:

ps -eaf -o pid,cmd | awk '/regex-to-match-command-name/{ print $1 }'