Reputation: 266
In my application there is a situation like this.Before creating a file, my application search for files in a directory under a particular filename. If any file/files found, then it should read each files contents and write these contents(of each file) to a new file. I have googled many and tried some like this:
string temp_file_format = "ScriptLog_" + DateTime.Now.ToString("dd_MM_yyyy_HH");
string[] files = Directory.GetFiles(path,temp_file_format);
foreach (FileAccess finfo in files)
{
string text = File.ReadAllText(finfo);
}
and
System.IO.DirectoryInfo dir = new DirectoryInfo(path);
System.IO.FileInfo[] files = dir.GetFiles(temp_file_format);
foreach (FileInfo finfo in files)
{
finfo.OpenRead();
}
But all these failed..Can anyone show me an alternative for this?
Is there anything wrong in my temp_file_format string?
It will be nice if I could prepend these contents to the new file. Else also, no worries..
any help would be really appreciated..
Upvotes: 1
Views: 1964
Reputation: 21742
Here's a short snippet that reads all the files and out puts them to the path outputPath
var lines = from file in Directory.GetFiles(path,temp_file_format)
from line in File.ReadAllLines(file)
select line;
File.WriteAllLines(outputPath, content);
The problem you are having with your code is not really related to reading files but simply trying to use an object as a type it's not. Directory.GetFiles
returns an array of string
and File.ReadXXX
and File.OpenRead
expects the path as a string. So you simply need to pass each of the strings returned as the path argument to the appropriate method. The above is one such example. Hope it helps both solve your problem and explain the actually issue with your code
Upvotes: 1
Reputation: 393064
This is a compete working implementation that does all of that
using System.IO;
using System.Linq;
public static class Program {
public static void Main()
{
var all = Directory.GetFiles("/tmp", "*.cpp")
.SelectMany(File.ReadAllLines);
using (var w = new StreamWriter("/tmp/output.txt"))
foreach(var line in all)
w.WriteLine(line);
}
}
I tested it on mono 2.10, and it should work on any .NET 4.0+ (for File.ReadAllLines
which is a lazy linewise enumerable)
Upvotes: 2
Reputation: 63065
using (var output = File.Create(outputPath))
{
foreach (var file in Directory.GetFiles(InputPath,temp_file_format))
{
using (var input = File.OpenRead(file))
{
input.CopyTo(output);
}
}
}
Upvotes: 0
Reputation: 835
try this:
foreach (FileInfo finfo in files)
{
try
{
using (StreamReader sr = new StreamReader("finfo "))
{
String line = sr.ReadToEnd();
Console.WriteLine(line);
}
}
catch (Exception e)
{
Console.WriteLine("The file could not be read:");
Console.WriteLine(e.Message);
}
}
Upvotes: 0