Reputation: 67847
I am new to python and don't know the best way to do this.
I have a list of tuples which represent points and another list which represents offsets. I need a set of all the combinations that this forms. Here's some code:
offsets = [( 0, 0),( 0,-1),( 0, 1),( 1, 0),(-1, 0)]
points = [( 1, 5),( 3, 3),( 8, 7)]
So my set of combined points should be
[( 1, 5),( 1, 4),( 1, 6),( 2, 5),( 0, 5),
( 3, 3),( 3, 2),( 3, 4),( 4, 3),( 2, 3),
( 8, 7),( 8, 6),( 8, 8),( 9, 7),( 7, 7)]
I'm not able to use NumPy or any other libraries.
Upvotes: 18
Views: 83010
Reputation: 882741
Personally, I like Alok's answer. However, for fans of itertools, the itertools-based equivalent (in Python 2.6 and later) is:
import itertools as it
ps = [(x+dx, y+dy) for (x, y), (dx, dy) in it.product(points, offsets)]
However, in this case the itertools solution is not faster than the simple one (it's actually a tad slower because it needs to unpack each x, y
repeatedly for every offset, while Alok's simple approach unpacks each x, y
but once). Still, itertools.product is an excellent alternative to nested loops in other cases, so, it's worth knowing about it!-)
Upvotes: 8
Reputation: 96251
result = [(x+dx, y+dy) for x,y in points for dx,dy in offsets]
For more, see list comprehensions.
Upvotes: 33
Reputation: 83032
If you don't care about duplicates in the result:
result = []
for ox, oy in offsets:
for px, py in points:
result.append((px + ox, py + oy))
If you do care about duplicates in the result:
result = set()
for ox, oy in offsets:
for px, py in points:
result.add((px + ox, py + oy))
Upvotes: 5
Reputation: 885
Pretty simple:
>>> rslt = []
>>> for x, y in points:
... for dx, dy in offsets:
... rslt.append( (x+dx, y+dy) )
...
>>> rslt
[(1, 5), (1, 4), (1, 6), (2, 5), (0, 5), (3, 3), (3, 2), (3, 4), (4, 3), (2, 3), (8, 7), (8, 6), (8, 8), (9, 7), (7, 7)]
Cycle through the points and the offsets, then build new tuples of adding the offsets to the points.
Upvotes: 15