Reputation: 2785
I have bellow html code and want to change
inline style
display:block
to
display:none
Where class is ln-b to ln-z
<div class="filter-div ln-b" style="display: block;"></div>
<div class="filter-div ln-c" style="display: block;"></div>
<div class="filter-div ln-d" style="display: block;"></div>
<div class="filter-div ln-e" style="display: block;"></div>
<div class="filter-div ln-f" style="display: block;"></div>
<div class="filter-div ln-g" style="display: block;"></div>
<div class="filter-div ln-h" style="display: block;"></div>
<div class="filter-div ln-i" style="display: block;"></div>
<div class="filter-div ln-j" style="display: block;"></div>
<div class="filter-div ln-k" style="display: block;"></div>
<div class="filter-div ln-l" style="display: block;"></div>
<div class="filter-div ln-m" style="display: block;"></div>
<div class="filter-div ln-n" style="display: block;"></div>
<div class="filter-div ln-o" style="display: block;"></div>
<div class="filter-div ln-p" style="display: block;"></div>
<div class="filter-div ln-q" style="display: block;"></div>
<div class="filter-div ln-r" style="display: block;"></div>
<div class="filter-div ln-s" style="display: block;"></div>
<div class="filter-div ln-t" style="display: block;"></div>
<div class="filter-div ln-u" style="display: block;"></div>
<div class="filter-div ln-v" style="display: block;"></div>
<div class="filter-div ln-w" style="display: block;"></div>
<div class="filter-div ln-x" style="display: block;"></div>
<div class="filter-div ln-y" style="display: block;"></div>
<div class="filter-div ln-z" style="display: block;"></div>
Any ideas or suggestions? Thanks.
Upvotes: 0
Views: 272
Reputation: 253318
I'd suggest (assuming they appear in that order and are siblings), and also that there's a .filter-div.ln-a
element that you don't want to hide:
$('.filter-div.ln-b').nextUntil($('.ln-z').next()).addBack().css('display','none');
References:
Upvotes: 3
Reputation: 3610
You can use:attr
$(".filter-div").attr('style', 'display:none');
Upvotes: 0
Reputation: 3740
$(".filter-div").css("display","none");
or
$('.filter-div').each(function() {
$(this).css("display","none");
}
Upvotes: 0