Reputation: 2124
What i am trying is - http://jsfiddle.net/jhrz9/1/
to remove the script generated when someone clicks the button #goBack button Now i am able to create and append script and style tags when the user clicks the #runMyCode But as soon as i go back to the previous screen using #goBack button the script stays on the screen, now what i want to do is to remove that script and create another one again when i click the #runMyCode button
Now i am trying this -
var newScript = document.createElement('script'); ;
var newTextNode=document.createTextNode($("#jsTextArea").val());
newScript.type = 'text/javascript';
newScript.appendChild(newTextNode);
document.body.appendChild(newScript);
$('#goBack').click(function(){
newTextNode.parentNode.removeChild(newTextNode);
});
But for some reason it is not working....
Upvotes: 1
Views: 9547
Reputation: 3339
you have to give the script an id.
$("#runMyCode").click(function(){
$("#resultContainer").html($("#htmlTextArea").val());
var newScript = document.createElement('script');
newScript.id = "goback_script";
var newTextNode=document.createTextNode($("#jsTextArea").val());
newScript.type = 'text/javascript';
newScript.appendChild(newTextNode);
document.body.appendChild(newScript);
var newStyle = document.createElement('style');
var newTextNode2=document.createTextNode($("#cssTextArea").val());
newStyle.type = 'text/css';
newStyle.appendChild(newTextNode2);
document.body.appendChild(newStyle);
});
$('#goBack').click(function(){
var script = document.getElementById("goback_script");
script.parentElement.removeChild(script);
});
Upvotes: 1