Tatu Ulmanen
Tatu Ulmanen

Reputation: 124778

Get parent directory of running script

In PHP, what would be the cleanest way to get the parent directory of the current running script relative to the www root? Assume I have:

$_SERVER['SCRIPT_NAME'] == '/relative/path/to/script/index.php'

Or just:

$something_else == '/relative/path/to/script/'

And I need to get /relative/path/to/ with slashes properly inserted. What would you suggest? A one liner is preferred.

EDIT

I need to get a path relative to the www root, dirname(__FILE__) gives me an absolute path in the filesystem so that won't work. $_SERVER['SCRIPT_NAME'] on the other hand 'starts' at the www root.

Upvotes: 89

Views: 144768

Answers (14)

babak Alizadeh
babak Alizadeh

Reputation: 11

$parentDirOfParent = dirname(__DIR__, 2);

if you want to get 2 level before use dirname just once with argument 2

Upvotes: 1

I hope this will help

function get_directory(){
    $s = empty($_SERVER["HTTPS"]) ? '' : ($_SERVER["HTTPS"] == "on") ? "s" : "";
    $protocol = substr(strtolower($_SERVER["SERVER_PROTOCOL"]), 0, strpos(strtolower($_SERVER["SERVER_PROTOCOL"]), "/")) . $s;
    $port = ($_SERVER["SERVER_PORT"] == "80") ? "" : (":".$_SERVER["SERVER_PORT"]);
return $protocol . "://" . $_SERVER['SERVER_NAME'] . dirname($_SERVER['PHP_SELF']);
}
define("ROOT_PATH", get_directory()."/" );
echo ROOT_PATH;

Upvotes: 0

Vignesh KM
Vignesh KM

Reputation: 2076

I Hope this will help you.

echo getcwd().'<br>'; // getcwd() will return current working directory
echo dirname(getcwd(),1).'<br>';
echo dirname(getcwd(),2).'<br>';
echo dirname(getcwd(),3).'<br>';

Output :

C:\wamp64\www\public_html\step
C:\wamp64\www\public_html
C:\wamp64\www
C:\wamp64

Upvotes: 6

John
John

Reputation: 21

This is a function that I use. Created it once so I always have this functionality:

function getDir(){
    $directory = dirname(__FILE__);
    $directory = explode("/",$directory);
    $findTarget = 0;
    $targetPath = "";
    foreach($directory as $dir){
        if($findTarget == 1){
            $targetPath = "".$targetPath."/".$dir."";
        }
        if($dir == "public_html"){
            $findTarget = 1;
        }
    }
    return "http://www.".$_SERVER['SERVER_NAME']."".$targetPath."";
}

Upvotes: 2

collidoscope
collidoscope

Reputation: 63

This is also a possible solution

$relative = '/relative/path/to/script/';
$absolute = __DIR__. '/../' .$relative;

Upvotes: 0

hans
hans

Reputation: 131

To get the parentdir of the current script.

$parent_dir = dirname(__DIR__);

Upvotes: 13

Charlie Vieillard
Charlie Vieillard

Reputation: 792

As of PHP 5.3.0 you can use __DIR__ for this purpose.

The directory of the file. If used inside an include, the directory of the included file is returned. This is equivalent to dirname(__ FILE__).

See PHP Magic constants.

C:\www>php --version
PHP 5.5.6 (cli) (built: Nov 12 2013 11:33:44)
Copyright (c) 1997-2013 The PHP Group
Zend Engine v2.5.0, Copyright (c) 1998-2013 Zend Technologies

C:\www>php -r "echo __DIR__;"
C:\www

Upvotes: 16

cestar
cestar

Reputation: 19

Try this. Works on both windows or linux server..

str_replace('\\','/',dirname(dirname(__FILE__)))

Upvotes: 1

Brad
Brad

Reputation: 51

Fugly, but this will do it:

substr($_SERVER['SCRIPT_NAME'], 0, strpos($_SERVER['SCRIPT_NAME'],basename($_SERVER['SCRIPT_NAME'])))

Upvotes: 5

Alex
Alex

Reputation: 9265

Here is what I use since I am not running > 5.2

function getCurrentOrParentDirectory($type='current')
{
    if ($type == 'current') {
        $path = dirname(__FILE__);  
    } else {
        $path = dirname(dirname(__FILE__));
    }
    $position = strrpos($path, '/') + 1;
    return substr($path, $position);
}

Double dirname with file as suggested by @mike b for the parent directory, and current directory is found by just using that syntax once.

Note this function only returns the NAME, slashes have to be added afterwards.

Upvotes: 2

Marco Demaio
Marco Demaio

Reputation: 34407

If I properly understood your question, supposing your running script is

/relative/path/to/script/index.php

This would give you the parent directory of your running script relative to the document www:

$parent_dir = dirname(dirname($_SERVER['SCRIPT_NAME'])) . '/';
//$parent_dir will be '/relative/path/to/'

If you want the parent directory of your running script relative to server root:

$parent_dir = dirname(dirname($_SERVER['SCRIPT_FILENAME'])) . '/';
//$parent_dir will be '/root/some/path/relative/path/to/'

Upvotes: 8

Tatu Ulmanen
Tatu Ulmanen

Reputation: 124778

Got it myself, it's a bit kludgy but it works:

substr(dirname($_SERVER['SCRIPT_NAME']), 0, strrpos(dirname($_SERVER['SCRIPT_NAME']), '/') + 1)

So if I have /path/to/folder/index.php, this results in /path/to/.

Upvotes: -7

Mike B
Mike B

Reputation: 32155

If your script is located in /var/www/dir/index.php then the following would return:

dirname(__FILE__); // /var/www/dir

or

dirname( dirname(__FILE__) ); // /var/www

Edit

This is a technique used in many frameworks to determine relative paths from the app_root.

File structure:

 /var/
      www/
          index.php
          subdir/
                 library.php

index.php is my dispatcher/boostrap file that all requests are routed to:

define(ROOT_PATH, dirname(__FILE__) ); // /var/www

library.php is some file located an extra directory down and I need to determine the path relative to the app root (/var/www/).

$path_current = dirname( __FILE__ ); // /var/www/subdir
$path_relative = str_replace(ROOT_PATH, '', $path_current); // /subdir

There's probably a better way to calculate the relative path then str_replace() but you get the idea.

Upvotes: 179

Jordan Ryan Moore
Jordan Ryan Moore

Reputation: 6887

$dir = dirname($file) . DIRECTORY_SEPARATOR;

Upvotes: 2

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