CODEWITHSUNDEEP
variablesawk
Tony
Tony

Reputation: 9581

awk line to variable?

I have the following command which exports out a date in milliseconds. I'm trying to have this stored as a variable so that I can use it later in my script:

epochlastUpdated= awk "/<pl:updated>/" feed.rss | head -n 1 | awk -F\< ' { print $2 } ' | awk -F\> ' { print $2 } '| date -j -f "%a, %d %b %Y %H:%M:%S %Z" "Fri, 13 Sep 2013 17:16:45 GMT" +%s000

I can't seem to get the script to have the output of that line stored in the epochlastUpdated variable?

Upvotes: 0

Views: 138

Answers (3)

Ed Morton
Ed Morton

Reputation: 203512

You got your specific answer but this:

awk "/<pl:updated>/" feed.rss | head -n 1 | awk -F\< ' { print $2 } ' | awk -F\> ' { print $2 } '

can be done in 1 awk command:

awk -F\< '/<pl:updated>/{split($2,a,/>/); print a[2]; exit}' feed.rss

It can probably be even simpler than that, it depends what your input actually looks like.

Upvotes: 2

Jotne
Jotne

Reputation: 41456

Another short awk version:

awk -F"<|>" '/<pl:updated>/ {print $3;exit}' feed.rss

Upvotes: 1

fedorqui
fedorqui

Reputation: 289725

To store a command execution result, you need

var=$(command)

In this case,

epochlastUpdated=$(awk "/<pl:updated>/" feed.rss | head -n 1 | awk -F\< ' { print $2 } ' | awk -F\> ' { print $2 } '| date -j -f "%a, %d %b %Y %H:%M:%S %Z" "Fri, 13 Sep 2013 17:16:45 GMT" +%s000)

Upvotes: 2

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