CODEWITHSUNDEEP
linuxbashawkgrep
laitha0
laitha0

Reputation: 4336

awk/sed/grep command to compare the contents of three files

Hi I am trying to automate some data entry, and I am using a tcp server/client to send filenames around for other server to go into a repository and pull these files. as part of testing this I am running the program with logging the filenames that are supposed to be sent, what was received, and if it got received I am sending a reply back with the filename.

so I have three text files with file names inside of them.

SupposedToSend.txt
Recieved.txt
GotReplyFor.txt

I know that awk could do what I am trying to do but I am not sure how to set it up, I need to compare the three files for elements that does not exists in any of the other files, so if one entry is missing from any file i need to know which one and from which file.

I can write a program for this which will take much longer to write and to run since these files are getting 5 elements/minute dumped into them

Upvotes: 0

Views: 225

Answers (1)

Anony
Anony

Reputation: 184

paste -d '\n' SupposedToSend.txt Recieved.txt GotReplyFor.txt | uniq -c | grep -v '^   3'

It's tolerable if you have no errors, deeply suboptimal otherwise. Or if the data in the different files is out of sequence... (In which case you might need to sort them somehow.)

Or you could just run diff3 to compare 3 files...

Upvotes: 2

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