CODEWITHSUNDEEP
php
Alex
Alex

Reputation: 71

Php error issue in while loop

I've a SMS Api which send sms(not email) to my client with php. Now I'm trying to send sms from .txt file where all contact number exist:

My .txt file 

shibbir, 8801678877639
babu, 8801534552503

So my while loop is look like this:

$file_handle = fopen("$file", "r");
while ( !feof( $file_handle ) ) {
    $line_of_text = fgetcsv($file_handle, 1024);
    $line_of_text[1] ."<BR>";       
    $obj = new Sender("myservername","myport","username","password","$sender", "$msg", 
"$line_of_text","2","1"); 
    $obj->Submit();     
    echo "<div class='success'>Successfully sent your message to " . $line_of_text[1] . " Thank 
    You.</div>";
}
fclose( $file_handle );

But I get following error message:

Notice: Array to string conversion in D:\Software Installed\xampp\htdocs\evan\toplevel
\bulksms.php on line 108

Notice: Undefined offset: 1 in D:\Software Installed\xampp\htdocs\evan\toplevel\bulksms.php on 
line 106

Notice: Undefined offset: 1 in D:\Software Installed\xampp\htdocs\evan\toplevel\bulksms.php on 
line 107

My final goal is, User can send sms by uploading .txt file where all contact number exit. So once it's submit the form then sms must be send to those contact number's.

  1. Can you guys tell me why i get error message ?
  2. And it's show 2 Success confirmation but i want it's must be show 1 success confirmation.

Thanks.

Upvotes: 1

Views: 75

Answers (4)

Mansoorkhan Cherupuzha
Mansoorkhan Cherupuzha

Reputation: 1761

Try this.

$file_handle = fopen("$file", "r");
$success_number = array();
    while ( !feof( $file_handle ) ) {
        $line_of_text = fgetcsv($file_handle, 1024);
        $success_number[]=$line_of_text[1]; //call this statement if msg sent successfully.
        $line_of_text  = implode(',',$line_of_text ); // i think we need to pass string to the api.
        $obj = new Sender("myservername","myport","username","password","$sender", "$msg", 
    "$line_of_text","2","1"); 
        $obj->Submit();     
    }
    echo "<div class='success'>Successfully sent your message to ".implode(',',$success_number) ."<BR> Thank You.</div>";
    fclose( $file_handle );

MY TEST

my.txt

shibbir, 8801678877639
babu, 8801534552503

my.php (removed the call to api)

    <?php
    $file = "my.txt";
    $file_handle = fopen($file, "r");
    $success_number = array();
    while ( !feof( $file_handle ) ) {
        $line_of_text = fgetcsv($file_handle, 1024);    
        $success_number[]=$line_of_text[1]; //call this statement if msg sent successfully.
    }
    fclose( $file_handle );
    echo "<div class='success'>Successfully sent your message to " . implode(',',$success_number) ."<BR> Thank You.</div>";
?>

OUTPUT 

    Successfully sent your message to 8801678877639, 8801534552503
Thank You.

Upvotes: 1

Charaf JRA
Charaf JRA

Reputation: 8334

Change this line :

$line_of_text[1] ."<BR>";

It should be :

$line_of_text[1] .= "<BR>";

and also your message is inside your loop , so it will be echoed more than once.

This task can be done easily using file() and explode()

Upvotes: 0

Shankar Narayana Damodaran
Shankar Narayana Damodaran

Reputation: 68536

1) Can you guys tell me why i get error message ?
2) And it's show 2 Success confirmation but i want it's must be show 1 success confirmation.

  1. They are not errors.

  2. Move the echo DIV tag out of your while loop.

Upvotes: 1

Gar
Gar

Reputation: 862

try changing your code into this

$file_handle = fopen("$file", "r");
while (!feof($file_handle) )
{
$line_of_text = fgetcsv($file_handle, 1024);
$line_of_text[1]=$line_of_text[1] ."<BR>";       
$obj = new Sender("myservername","myport","username","password","$sender", "$msg", 
$line_of_text[1],"2","1"); 
$obj->Submit();     
echo "<div class='success'>Successfully sent your message to " . $line_of_text[1] . " Thank 
You.</div>";
}
fclose($file_handle);

Upvotes: 1

Related Questions