CODEWITHSUNDEEP
php
Andrew
Andrew

Reputation: 238717

PHP: How to turn an array into a StdClass object?

Is there a PHP function that will do this automatically?

if (is_array($array)) {
    $obj = new StdClass();
    foreach ($array as $key => $val){
        $obj->$key = $val;
    }
    $array = $obj;
}

Upvotes: 5

Views: 615

Answers (3)

Devrim
Devrim

Reputation: 2904

This works for me

if (is_array($array)) {
$obj = new StdClass();
foreach ($array as $key => $val){

    $key = str_replace("-","_",$key) 

    $obj->$key = $val;
}
$array = $obj;
}

make sure that str_replace is there as '-' is not allowed within variable names in php, as well as:

Naming Rules for Variables

* A variable name must start with a letter or an underscore "_"
* A variable name can only contain alpha-numeric characters and underscores (a-z, A-Z, 0-9, and _ )
* A variable name should not contain spaces. If a variable name is more than one word, it should be separated with an underscore ($my_string), or with capitalization ($myString)

So, since these are permitted in arrays, if any of them comes in the $key from the array you are converting, you will have nasty errors.

Upvotes: 0

Sampson
Sampson

Reputation: 268344

Why not just cast it?

$myObj = (object) array("name" => "Jonathan");
print $myObj->name; // Jonathan

If it's multidimensional, Richard Castera provides the following solution on his blog:

function arrayToObject($array) {
  if(!is_array($array)) {
    return $array;
  }
  $object = new stdClass();
    if (is_array($array) && count($array) > 0) {
      foreach ($array as $name=>$value) {
        $name = strtolower(trim($name));
          if (!empty($name)) {
            $object->$name = arrayToObject($value);
          }
      }
      return $object; 
    } else {
      return FALSE;
    }
}

Upvotes: 10

Pekka
Pekka

Reputation: 449425

If it's a one-dimensional array, a cast should work:

$obj = (object)$array;

Upvotes: 3

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