Reputation: 379
I have this code which prints:
[( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), ( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]
I tried to split at [#] but it didnt work.
What should i put in split so that I can get as a result the part after # only: Hello, Bye
Query query = QueryFactory.create(queryString);
QueryExecution qe= QueryExecutionFactory.create(query, model);
ResultSet resultset = qe.execSelect();
ResultSet results = ResultSetFactory.copyResults(resultset);
final ResultSet results2 = ResultSetFactory.copyResults(results);
System.out.println( "== Available Options ==" );
ResultSetFormatter.out(System.out, results, query);
Scanner input = new Scanner(System.in);
final String inputs;
inputs = input.next();
final String[] indices = inputs.split("\\s*,\\s*");
final List<QuerySolution> selectedSolutions = new ArrayList<QuerySolution>(
indices.length) {
{
final List<QuerySolution> solutions = ResultSetFormatter
.toList(results2);
for (final String index : indices) {
add(solutions.get(Integer.valueOf(index)));
}
}
};
System.out.println(selectedSolutions);
Upvotes: 3
Views: 606
Reputation: 42010
Try the regular expression:
(?<=#)([^#>]+)
e.g.:
private static final Pattern REGEX_PATTERN =
Pattern.compile("(?<=#)([^#>]+)");
public static void main(String[] args) {
String input = "[( ?A = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), ( ?A = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#World> )]";
Matcher matcher = REGEX_PATTERN.matcher(input);
while (matcher.find()) {
System.out.println(matcher.group());
}
}
Output:
Hello
World
Upvotes: 0
Reputation: 48404
If I understand correctly, you only want to extract "Hello" and "Bye" from your input String through regex.
In which case, I would just use iterative matching of whatever's in between #
and >
, as such:
// To clarify, this String is just an example
// Use yourScannerInstance.nextLine to get the real data
String input = "[( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Hello> ), "
+ "( ?Random = <http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]";
// Pattern improved by Brian
// was: #(.+?)>
Pattern p = Pattern.compile("#([^>]+)>");
Matcher m = p.matcher(input);
// To clarify, printing the String out is just for testing purpose
// Add "m.group(1)" to a Collection<String> to use it in further code
while (m.find()) {
System.out.println(m.group(1));
}
Output:
Hello
Bye
Upvotes: 7
Reputation: 35547
You can try this
String[] str= your_orginal_String.split(",");
Then you can take the parts after # as follows
String[] s=new String[2];
int j=0;
for(String i:str){
s[j]=i.split("#",2)[1];
j++;
}
You may need some formatting. for resulting String[] s
as follows
String str = "[( ?Random = <http://www.semanticweb.org/vassilis
/ontologies/2013/5/Test#Hello> ), ( ?Random =
<http://www.semanticweb.org/vassilis/ontologies/2013/5/Test#Bye> )]";
String[] arr = str.split(",");
String[] subArr = new String[arr.length];
int j = 0;
for (String i : arr) {
subArr[j] = i.split("#", 2)[1].replaceAll("\\>|\\)|\\]", "");
j++;
}
System.out.println(Arrays.toString(subArr));
Out put:
[Hello , Bye ]
Upvotes: 2