CODEWITHSUNDEEP
bash
Ben
Ben

Reputation: 984

Bash: list all the directories for which only contains two subfolders: folder1 and folder2?

As in the title, can someone help to answer this only using the Bash?

I spent some time can't figure it out. Thanks.

Upvotes: 1

Views: 235

Answers (2)

konsolebox
konsolebox

Reputation: 75478

This would list those directories without being redundant on searches.

#!/bin/bash

function check {
    local DIR SUBFOLDERS=()
    for DIR; do
        readarray -t SUBFOLDERS < <(find "$DIR" -maxdepth 1 -mindepth 1 -type d)
        if [[ ${#SUBFOLDERS[@]} -gt 0 ]]; then
            [[ ${#SUBFOLDERS[@]} -eq 2 ]] && echo "$DIR"
            check "${SUBFOLDERS[@]}"
        fi
    done
}

check "$@"

Run the script with

bash script.sh dir_to_search [optionally_another_dir_to_search ...]

Examples:

bash script.sh .
bash script.sh "$HOME"
bash script.sh /var /usr

Upvotes: 1

devnull
devnull

Reputation: 123458

The following should list the directories containing only two folders folder1 and folder2.

for i in $(find . -type d); do count=$(find $i -mindepth 1 -maxdepth 1 -type d | wc -l); [ $count -eq 2 ] && [ -d $i/folder1 ] && [ -d $i/folder2 ] && echo $i ; done

The above wouldn't care if the folders have other files. If you want to ensure only directories folder1 and folder2, say:

for i in $(find . -type d); do count=$(find $i -mindepth 1 -maxdepth 1 | wc -l); [ $count -eq 2 ] && [ -d $i/folder1 ] && [ -d $i/folder2 ] && echo $i ; done

[Be warned that the above might not work with spaces in directory names.]

Upvotes: 3

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