CODEWITHSUNDEEP
datetimecalculatorclocksubtraction
Jordan Carpenter
Jordan Carpenter

Reputation: 1

how do i subtract variables in a 24 hour clock?

This is what I have so far

H1 = input("insert hour 0-23 :")
M1 = input("insert minute 1-60 :")
S1 = input("insert second :")
print H1,":",M1,":",S1

H2 = input("insert hour 0-23 :")
M2 = input("insert minute 1-60 :")
S2 = input("insert second 1-60 :")
print H2,":",M2,",",S2

where I am stuck is getting the difference between the two times and also converting the difference into seconds.

Which I think after I've properly got the difference would not be to hard when I've tried things like (H3 = H2 - H1 or H3 = H1 - H2) if the first number is lower than the second I obviously get a negative number which I do not want

I want the numbers to go along with a 24 hour clock

Upvotes: 0

Views: 428

Answers (1)

lmNt
lmNt

Reputation: 3892

One way would be to use modulo subtraction (Modular Arithmetics).

Just perform something like that:

mRemainder, hRemainder = 0;
S = (S1 - S2) mod 60;
if (S1 < S2) mRemainder = 1;
M = (M1 - M2 - mRemainder) mod 60;
if (M1 < M2 + mRemainder) hRemainder = 1;
H = (H1 - H2 - hRemainder) mod 24;

Upvotes: 1

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