Reputation: 1912
I'm trying to create a 3-dimensional NNN list in Python, like such:
n=3
l = [[[0,]*n]*n]*n
Unfortunately, this does not seem to properly "clone" the list, as I thought it would:
>>> l
[[[0, 0, 0], [0, 0, 0], [0, 0, 0]], [[0, 0, 0], [0, 0, 0], [0, 0, 0]], [[0, 0, 0], [0, 0, 0], [0, 0, 0]]]
>>> l[0][0][0]=1
>>> l
[[[1, 0, 0], [1, 0, 0], [1, 0, 0]], [[1, 0, 0], [1, 0, 0], [1, 0, 0]], [[1, 0, 0], [1, 0, 0], [1, 0, 0]]]
What am I doing wrong here?
Upvotes: 2
Views: 1228
Reputation: 20528
I have to second what leonardo-santagada suggested, with the addition that creating N dimensional arrays/lists is very unpythonic and you should reconsider how you're keeping your data and seeing if it doesn't belong better in a class or a list of dictionaries (or dictionaries of lists).
Upvotes: 2
Reputation: 146
If you want to do numerical processing with 3-d matrix you are better of using numpy. It is quite easy:
>>> import numpy
>>> numpy.zeros((3,3,3), dtype=numpy.int)
array([[[0, 0, 0],
[0, 0, 0],
[0, 0, 0]],
[[0, 0, 0],
[0, 0, 0],
[0, 0, 0]],
[[0, 0, 0],
[0, 0, 0],
[0, 0, 0]]])
>>> _[0,0,0]
0
Upvotes: 4
Reputation: 19872
As others have mentioned, it's building the 2nd and 3rd levels with references, not clones. Try:
>>> n = 3
>>> l = [[[0]*n for _ in xrange(n)] for _ in xrange(n)]
>>> l[0][0][0] = 1
>>> l
[[[1, 0, 0], [0, 0, 0], [0, 0, 0]], [[0, 0, 0], [0, 0, 0], [0, 0, 0]], [[0, 0, 0], [0, 0, 0], [0, 0, 0]]]
Or if you want to type a bit less:
>>> l = [[[0]*n for _ in '.'*n] for _ in '.'*n]
Upvotes: 3
Reputation: 10872
The problem is that * n
does a shallow copy of the list. A solution is to use nested loops, or try the numpy library.
Upvotes: 5
Reputation: 5394
It's not cloning the list. It's inserting a reference to the same list over and over. Try creating the list using a set of nested for loops.
Upvotes: 2