CODEWITHSUNDEEP
xmlxslt
Maxime Carbonneau-Leclerc
Maxime Carbonneau-Leclerc

Reputation: 87

XSL count parent node not having a child node with a certain attribute

I have an xml file with a certain node ( parentNode in this case ) and I want to know how many specialNode has no childNode having a certain attribute.

Example:

<parentNode>
    <specialNode>
        <childNode attrib=true />
        <childNode attrib=false />
    </specialNode>
    <specialNode>
        <childNode attrib=true />
        <childNode attrib=true />
    </specialNode>
    <specialNode>
        <childNode attrib=false />
    </specialNode>
</parentNode>

I would like to call something like :

<xsl:variable="foo" select="count( not( */specialNode/childNode[ attrib="true" ] ) ) />

... and to have foo = 1 because there is only one specialNode where all its child node has attrib = false.

Is there a way to do this?

Upvotes: 1

Views: 464

Answers (1)

kstubs
kstubs

Reputation: 808

count(/parentNode/specialNode[not(childNode[@attrib='true'])])

Here is the corrected XML

<parentNode>
    <specialNode>
        <childNode attrib="false"/>
        <childNode attrib="false"/>
    </specialNode>
    <specialNode>
        <childNode attrib="true"/>
        <childNode attrib="true"/>
    </specialNode>
    <specialNode>
        <childNode attrib="false"/>
    </specialNode>
</parentNode>

Upvotes: 1

Related Questions