CODEWITHSUNDEEP
bashgrepwildcard
tomocafe
tomocafe

Reputation: 1544

Using * in grep path called from bash script

I'm trying to write a bash script to search my source directories for a string using grep -- and no, I can't use ack.

The directory structure is

Headers: .../product/package/product-module/i/filename.h

Source: .../product/package/product-module/s/filename.c

I'd like the option to specify module or not (search all modules), which is the point of argument $2. Problem is, I can't get either *$2 or "*$2" to work in the script (please see below).

edit: The former attempt results in no output whatsoever, and the latter results in "grep: No such file or directory"

How do I correctly use * with grep if I want to compound it with another string?

#!/bin/bash

# Usage: search_src -[si] < module | all > < target >

if [ $1 == "-s" ]; then
   fext="c"
   subdir="s"
elif [ $1 == "-i" ]; then
   fext="h"
   subdir="i"
else
   fext="[ch]"
   subdir="[si]"
fi

if [ $2 == "all" ]; then
   module=*;
else
   module=*$2;
fi

shift 2;

grep \"$@\" ~/workspace/*/package/$module/$subdir/*.$fext

Upvotes: 1

Views: 287

Answers (1)

konsolebox
konsolebox

Reputation: 75488

Just use a safe eval and some minor modifications:

#!/bin/bash

# Usage: search_src -[si] < module | all > < target >

if [[ $1 == "-s" ]]; then
   fext="c"
   subdir="s"
elif [[ $1 == "-i" ]]; then
   fext="h"
   subdir="i"
else
   fext="[ch]"
   subdir="[si]"
fi

if [[ $2 == "all" ]]; then
   module='*';
else
   module='*"$2"';
fi

shopt -s nullglob
eval "files=(~/workspace/*/package/$module/$subdir/*.$fext)"

IFS=$' \t\n'
[[ $# -gt 2 && ${#files[@]} -gt 0 ]] && grep -e "${*:3}" -- "${files[@]}"

Upvotes: 3

Related Questions