CODEWITHSUNDEEP
javascriptnode.jsexpress
Nabil Djarallah
Nabil Djarallah

Reputation: 813

Node.js: get path from the request

I have a service called "localhost:3000/returnStat" that should take a file path as parameter. For example '/BackupFolder/toto/tata/titi/myfile.txt'.

How can I test this service on my browser? How can I format this request using Express for instance?

exports.returnStat = function(req, res) {

var fs = require('fs');
var neededstats = [];
var p = __dirname + '/' + req.params.filepath;

fs.stat(p, function(err, stats) {
    if (err) {
        throw err;
    }
    neededstats.push(stats.mtime);
    neededstats.push(stats.size);
    res.send(neededstats);
});
};

Upvotes: 80

Views: 239190

Answers (8)

Mistico
Mistico

Reputation: 355

I've used this const { pathname } = req?._parsedUrl || {}; and it worked for me

Upvotes: 0

kano
kano

Reputation: 5920

A more modern solution that utilises the URL WebAPI:

(req, res) => {
  const { pathname } = new URL(req.url || '', `https://${req.headers.host}`)
}

Upvotes: 7

loretoparisi
loretoparisi

Reputation: 16271

Combining solutions above when using express request:

let url=url.parse(req.originalUrl);
let page = url.parse(uri).path?url.parse(uri).path.match('^[^?]*')[0].split('/').slice(1)[0] : '';

this will handle all cases like

localhost/page
localhost:3000/page/
/page?item_id=1
localhost:3000/
localhost/

etc. Some examples:

> urls
[ 'http://localhost/page',
  'http://localhost:3000/page/',
  'http://localhost/page?item_id=1',
  'http://localhost/',
  'http://localhost:3000/',
  'http://localhost/',
  'http://localhost:3000/page#item_id=2',
  'http://localhost:3000/page?item_id=2#3',
  'http://localhost',
  'http://localhost:3000' ]
> urls.map(uri => url.parse(uri).path?url.parse(uri).path.match('^[^?]*')[0].split('/').slice(1)[0] : '' )
[ 'page', 'page', 'page', '', '', '', 'page', 'page', '', '' ]

Upvotes: -1

Gaurav
Gaurav

Reputation: 2103

var http = require('http');
var url  = require('url');
var fs   = require('fs');

var neededstats = [];

http.createServer(function(req, res) {
    if (req.url == '/index.html' || req.url == '/') {
        fs.readFile('./index.html', function(err, data) {
            res.end(data);
        });
    } else {
        var p = __dirname + '/' + req.params.filepath;
        fs.stat(p, function(err, stats) {
            if (err) {
                throw err;
            }
            neededstats.push(stats.mtime);
            neededstats.push(stats.size);
            res.send(neededstats);
        });
    }
}).listen(8080, '0.0.0.0');
console.log('Server running.');

I have not tested your code but other things works

If you want to get the path info from request url

 var url_parts = url.parse(req.url);
 console.log(url_parts);
 console.log(url_parts.pathname);

1.If you are getting the URL parameters still not able to read the file just correct your file path in my example. If you place index.html in same directory as server code it would work...

2.if you have big folder structure that you want to host using node then I would advise you to use some framework like expressjs

If you want raw solution to file path

var http = require("http");
var url = require("url");

function start() {
function onRequest(request, response) {
    var pathname = url.parse(request.url).pathname;
    console.log("Request for " + pathname + " received.");
    response.writeHead(200, {"Content-Type": "text/plain"});
    response.write("Hello World");
    response.end();
}

http.createServer(onRequest).listen(8888);
console.log("Server has started.");
}

exports.start = start;

source : http://www.nodebeginner.org/

Upvotes: 89

kumbhani bhavesh
kumbhani bhavesh

Reputation: 2257

You can use this in app.js file .

var apiurl = express.Router();
apiurl.use(function(req, res, next) {
    var fullUrl = req.protocol + '://' + req.get('host') + req.originalUrl;
    next();
});
app.use('/', apiurl);

Upvotes: 8

Xin
Xin

Reputation: 36520

req.protocol + '://' + req.get('host') + req.originalUrl

or

req.protocol + '://' + req.headers.host + req.originalUrl // I like this one as it survives from proxy server, getting the original host name

Upvotes: 5

Ideabile
Ideabile

Reputation: 181

Based on @epegzz suggestion for the regex.

( url ) => {
  return url.match('^[^?]*')[0].split('/').slice(1)
}

returns an array with paths.

Upvotes: 3

Sagiv Ofek
Sagiv Ofek

Reputation: 25270

simply call req.url. that should do the work. you'll get something like /something?bla=foo

Upvotes: 18

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