Reputation: 197
Im a Totally new in Java and JSF. I'm using eclipse Indigo and Tomcat 6.0.3 and JSF 2.0. Iam using the Maven and deploying the wars to server.
I configured the server in the Eclipse and i normally get the apache page in Localhost:8080.
But When i try to access my page like localhost:8080/ContactFormJSF/, I get the Message as
HTTP Status 404 - /ContactFormJSF/
type Status report
message /ContactFormJSF/
description The requested resource (/ContactFormJSF/) is not avilable.
This is code like, what there in Adduser.xhtml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:h="http://java.sun.com/jsf/html">
<h:head>
<title>JSF 2.0 Hello World</title>
</h:head>
<h:body>
<h3>JSF 2.0 Hello World Example - hello.xhtml</h3>
</h:body>
</html>
I Have even configured the "servlet-mapping
","welcome-file-list
" in the Web.xml
My web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee">
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.xhtml</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>AddUser.xhtml</welcome-file>
</welcome-file-list>
<context-param>
<param-name>javax.faces.PROJECT_STAGE</param-name>
<param-value>Development</param-value>
</context-param>
<session-config>
<session-timeout>15</session-timeout>
</session-config>
</web-app>
Upvotes: 0
Views: 627
Reputation: 4853
Check the following Conditions
WEB-INF/lib
directory(Strongly recommended)servlet
has been mapped in Web.xml
URL
pattern in browserUpvotes: 1