CODEWITHSUNDEEP
phpwordpressfunction
Joshc
Joshc

Reputation: 3853

php function add foreach array on another array to populate a select drop down

I started this PHP function. This function is to populate a dropdown select menu in WordPress.

The acf/load_field hook helps me easily hook this in. See documentation here. http://www.advancedcustomfields.com/resources/filters/acfload_field/

This is my function which uses get_posts to query my circuit post_type. This bit works fine.

See below...

function my_circuit_field( $field )
{
    $circuits = get_posts(array(
        "post_type" => "circuit",
        "post_status" => "publish",
        "orderby" => "menu_order",
        "order" => "ASC",
        "posts_per_page"  => -1
    ));
    $field['choices'] = array();
    $field['choices'] = array(
        0 => 'Select a circuit...'
    );
    foreach($circuits as $circuit){
        $field['choices'] = array(
            $circuit->post_title => $circuit->post_title
        );
    }       
    return $field;
}
add_filter('acf/load_field/name=event_calendar_circuit', 'my_circuit_field');



The problem I am having is that...

$field['choices'] = array(
    0 => 'Select a circuit...'
);

is not joining onto the front of this...

foreach($circuits as $circuit){
    $field['choices'] = array(
         $circuit->post_title => $circuit->post_title
    );
}


Only the $circuits foreach is showing in my dropdown, I would like 'Select a circuit' to appear as the first option in the dropdown select menu.

Can anyone help me understand where I am going wrong?

Upvotes: 1

Views: 359

Answers (2)

Code Lღver
Code Lღver

Reputation: 15603

Use this:

$field['choices'] = array(
    0 => 'Select a circuit...'
);
$arr = array();
foreach($circuits as $circuit){
    $arr = array(
       $circuit->post_title => $circuit->post_title
    );
    $field['choices'] = array_merge($field['choices'],$arr);
}
print_r($field);

OUTPUT:

Array
(
    [choices] => Array
        (
            [0] => Select a circuit...
            //and other fields 
            //with the 0 index value
            //same as you are requiring
        )
)

Upvotes: 1

Kethryweryn
Kethryweryn

Reputation: 639

When you use =, it replaces the current value with the one after the = sign. You're replacing the whole value of $field['choices'] each time you assign a new value.

You probably want to do something like

foreach($circuits as $circuit){
    $field['choices'][$circuit->post_title] = $circuit->post_title;
}

By the way, the line $field['choices'] = array(); is useless in your code, as you change the value in the following line.

Upvotes: 1

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