BDR
BDR

Reputation: 464

Bash IF : multiple conditions

I've been trying to make this thing work for a couple of hours but I can't get it to work :

if [ "$P" = "SFTP" -a "$PORT" != "22" ] || [ "$P" = "FTPS" && [ "$PORT" != "990" -a "$PORT" != "21" ] ] ; then

Can someone help me ? I know that multiple conditions can be written like this :

if [ "$P" = "SFTP" ] && [ "$PORT" != "22" ]; then

but how can I imbricate theses conditions like in my first example?

Upvotes: 6

Views: 5432

Answers (1)

user000001
user000001

Reputation: 33317

You can't nest expressions in single brackets. It should be written like this:

if [ "$P" = "SFTP" -a "$PORT" != "22" ] || [ "$P" = "FTPS" -a "$PORT" != "990" -a "$PORT" != "21" ] ; then

This can be written as a single expressions as:

if [ \( "$P" = "SFTP" -a "$PORT" != "22" \) -o \( "$P" = "FTPS" -a "$PORT" != "990" -a "$PORT" != "21" \) ] ; then

although is is not fully compatible with all shells.

Since you are using bash, you can use double brackets to make the command more readable:

if [[ ( $P = "SFTP" && $PORT != "22" ) || ( $P = "FTPS" && $PORT != "990" && $PORT != "21" ) ]] ; then

Upvotes: 11

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