CODEWITHSUNDEEP
regex
nedblorf
nedblorf

Reputation: 5365

Regex to get all character to the right of first space?

I am trying to craft a regular expression that will match all characters after (but not including) the first space in a string.

Input text:

foo bar bacon

Desired match:

bar bacon

The closest thing I've found so far is:

\s(.*)

However, this matches the first space in addition to "bar bacon", which is undesirable. Any help is appreciated.

Upvotes: 2

Views: 9650

Answers (4)

Andy Lester
Andy Lester

Reputation: 93676

You don't need look behind.

my $str = 'now is the time';
# Non-greedily match up to the first space, and then get everything after in a group.
$str =~ /^.*? +(.+)/; 
my $right_of_space = $1; # Keep what is in the group in parens
print "[$right_of_space]\n";

Upvotes: 2

konsolebox
konsolebox

Reputation: 75488

I'd prefer to use [[:blank:]] for it as it doesn't match newlines just in case we're targetting mutli's. And it's also compatible to those not supporting \s.

(?<=[[:blank:]]).*

Upvotes: 3

Anirudha
Anirudha

Reputation: 32797

You can also try this

(?s)(?<=\S*\s+).*

or

(?s)\S*\s+(.*)//group 1 has your match

With (?s) . would also match newlines

Upvotes: 1

arshajii
arshajii

Reputation: 129507

You can use a positive lookbehind:

(?<=\s).*

(demo)

Although it looks like you've already put a capturing group around .* in your current regex, so you could just try grabbing that.

Upvotes: 5

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