Reputation: 1744
I am writing a mysql query and I have a question. Can I / How do I do something like this:
select rating, user_id, (
-- in here I want to write a subquery to get the number of times the user_id in the outter query has rated this teacher
) as user_rated_frequency from teachers_rating where teacher_id = id
Essentially I am trying to get data and the frequency in which that user rated that teacher. Is it possible to use an alias from one of the items I want to select in a subquery that is still in the select and not in the where clause?
Upvotes: 11
Views: 42712
Reputation: 13957
Check out this ...
SELECT rating,
user_id,
(SELECT COUNT(*)
FROM teachers_rating t1
WHERE teacher_id = 3
AND t1.user_id = t2.user_id) AS user_rated_frequency
FROM teachers_rating t2
WHERE teacher_id = 3;
or that one:
SELECT AVG (rating) AS average_rating,
user_id,
(SELECT Count(*)
FROM teachers_rating t1
WHERE teacher_id = 3
AND t1.user_id = t2.user_id) AS user_rated_frequency
FROM teachers_rating t2
WHERE teacher_id = 3
GROUP BY user_rated_frequency;
Links above show a SQL Fiddle example assuming that id
is 3
.
Alternatively you could have a sub query in the FROM
clause:
SELECT AVG (t1.rating),
t1.user_id,
t2.user_rated_frequency
FROM teachers_rating t1,
(SELECT tr.teacher_id,
tr.user_id,
COUNT(*) AS user_rated_frequency
FROM teachers_rating tr
GROUP BY tr.teacher_id) t2
WHERE t1.teacher_id = t2.teacher_id
AND t1.user_id = t2.user_id
GROUP BY user_id, user_rated_frequency
Hat a look at this Fiddle.
Upvotes: 23
Reputation: 8703
You need to move your subquery (technically called a derived table) into your from clause. Something like so:
select
rating,
user_id,
from teachers_rating,
(in here I want to write a subquery to get the number of times the user_id in the outter query has rated this teacher) as user_rated_frequency f
where teacher_id = f.id
Upvotes: -1