Reputation: 178
In our programming environment at work we have both Java and C# developers. I have a web service I created In C# that the Java developers are trying to consume. I have been writing the Java to consume this web service and while I am getting a json result, it is in the wrong format.
Here is what I have on the c# side:
[WebMethod]
public static LinkedList<string> GetInfo(string InfoID, string Username, string Password)
{
LinkedList<string> Result = new LinkedList<string>();
try
{
// Do some stuff I can't show you to get the information...
foreach (Result from data operations)
{
Result.AddLast(sample1);
Result.AddLast(sample2);
Result.AddLast(sample3);
Result.AddLast(BD));
Result.AddLast(CN);
Result.AddLast(Name);
Result.AddLast("###");
}
}catch(Exception exc)
{
Result.AddLast(exc.ToString());
return Result;
}
return Result;
}
Then this is the Java Side:
try {
String uri = "http://example.com/service.asmx/GetInfo";
URL url = new URL(uri);
HttpURLConnection connection = (HttpURLConnection) url.openConnection();
// Setup Connection Properties
connection.setRequestMethod("POST");
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("charset", "utf-8");
connection.setRequestProperty("Accept", "application/json");
connection.setChunkedStreamingMode(0);
connection.connect();
// Create the JSON Going out
byte[] parameters = "{'InfoID':'123456789','Username':'usernametoken','Password':'passwordtoken'}".getBytes("UTF-8");
// Start doing stuff
DataOutputStream os = new DataOutputStream(connection.getOutputStream());
os.write(parameters);
os.close();
InputStream response;
// Check for error , if none store response
if(connection.getResponseCode() == 200){response = connection.getInputStream();}
else{response = connection.getErrorStream();}
InputStreamReader isr = new InputStreamReader(response);
StringBuilder sb = new StringBuilder();
BufferedReader br = new BufferedReader(isr);
String read = br.readLine();
while(read != null){
sb.append(read);
read = br.readLine();
}
// Print the String
System.out.println(sb.toString());
// Creat JSON off of String
JSONObject token = new JSONObject(sb.toString());
// print JSON
System.out.println("Tokener: " + token.toString());
response.close();
} catch(IOException exc) {
System.out.println("There was an error creating the HTTP Call: " + exc.toString());
}
And the response I get is in this form...
{"d":["Sample1","Sample2","Sample3","BD","CN","Name","###","Sample1","Sample2","Sample3","BD","CN","Name","###","Sample1","Sample2","Sample3","BD","CN","Name","###"]}
I was wondering if there was a better way to send the response such that the JSON would look like this:
{"1":["Sample1","Sample2","Sample3","BD","CN","Name","###"],"2":["Sample1","Sample2","Sample3","BD","CN","Name","###"],"3":["Sample1","Sample2","Sample3","BD","CN","Name","###"],"4":["Sample1","Sample2","Sample3","BD","CN","Name","###"]}
Upvotes: 0
Views: 1877
Reputation: 6260
Ok I think I see your problem here. You want your data to be serialized as
{"1":["Sample1","Sample2","Sample3","BD","CN","Name","###"],"2":["Sample1","Sample2","Sample3","BD","CN","Name","###"],"3":["Sample1","Sample2","Sample3","BD","CN","Name","###"] ... etc
Yet the data structure you are serializing is a single linked list, which is why it is serialized as a single long list. What you need to do is change the data structure. A Dictionary
would be perfect, since it is easily serializable as JSON.
[ScriptMethod(ResponseFormat = ResponseFormat.Json)]
[WebMethod]
public static Dictionary<int,LinkedList<string>> GetInfo(string InfoID, string Username, string Password)
{
var Result = new Dictionary<int,LinkedList<string>>();
try
{
// Do some stuff I can't show you to get the information...
foreach (Result from data operations)
{
var newList = new LinkedList<string>();
newList.AddLast(sample1);
newList.AddLast(sample2);
newList.AddLast(sample3);
newList.AddLast(BD));
newList.AddLast(CN);
newList.AddLast(Name);
newList.AddLast("###");
int number = something //the number before the list
Result.add( number, newList);
}
}catch(Exception exc)
{
.
.
.
}
return Result;
}
Upvotes: 1